Answer:
18245
Step-by-step explanation:
We have to use L.C.M,
L.C.M(20,24,32,38)
2|20,24,32,38
2| 10 ,12 ,16 ,19
2| 5 , 6 , 8 , 19
2| 5 , 3 , 4 , 19
2| 5 , 3 , 2 , 19
L.C.M = 2 x 2 x 2 x 2 x 2 x 2 x 5 x 3 x 19
= 18240
Now for each case remainder is 5,
So the number is 18240+5
=> 18245
3 are expected to have the condition.
The expected value is the found by multiplying the probability by the number in the sample:
(1/200)×600
= (1/200)×(600/1)
= (1×600)/(200×1)
= 600/200 = 3
Answer:
x = 1
Step-by-step explanation:
They intersect at ONE point.
