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rosijanka [135]
3 years ago
8

In a pack of candies, Marla found that for every 3 blue candies, there were 5 red one. Identify the correct list of ratios that

compress that red candies to the blue ones.
Mathematics
1 answer:
chubhunter [2.5K]3 years ago
7 0

Answer:

\frac{5}{3} is the ratio that compress that red candies to the blue ones.

Step-by-step explanation:

We have been given the pack of candies

For every 3 blue candies there were 5 red candies.

So, we need to find the list of ratio that compress red candies to the blue ones

So, the required ratio will be: \frac{5}{3}

\frac{5}{3} is the ratio that compress that red candies to the blue ones.

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The Hiking Club plans to go camping in a State park where the probability of rain on
Margarita [4]

Answer:

3/4 or 0.75

Step-by-step explanation:

4 0
3 years ago
-<br><img src="https://tex.z-dn.net/?f=%20-%203%5Cpi%20%2B%20w%20%3D%202%5Cpi" id="TexFormula1" title=" - 3\pi + w = 2\pi" alt="
pantera1 [17]

Isolate the w. Note the equal sign. What you do to one side, you do to the other.

Add 3π to both sides

- 3π (+3π) + w = 2π (+3π)

w = 2π + (3π)

w = 5π

w = 5π is your answer

hope this helps

4 0
3 years ago
What are the common multipls of 2 and 3 between 2 and 25
Colt1911 [192]

Answer:

6, 12, 18, and 24

Step-by-step explanation:

Multiples of 2: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24. Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24. Common multiples of 2 and 3 include 6, 12, 18, and 24.

4 0
3 years ago
What should be the b-value in the equation shown below if the equation is a perfect square trinomial?
masha68 [24]

Answer:

B=10

Step-by-step explanation:

It's a perfect square of equation ax²+2abx+b²

I'm the given equation a is 1 and b is 5 so 2(a)(b)=2(1)(5)=10

(ps: when I say b in the explanation I mean another b not the one in question as to not be confused)

4 0
2 years ago
Find the second derivative, do not have to simplify
zlopas [31]

f(x)=\sec(\pi x)=\dfrac{1}{\cos(\pi x)}=[\cos(\pi x)]^{-1}\\\\\text{use}\\\\(a^n)'=na^{n-1}\\\\(\cos x)'=-\sin x\\\\f'(g(x))=f'(g(x))\cdot g'(x)

f'(x)=\left\{[\cos(\pi x)]^{-1}\right\}'=-[\cos(\pi x)]^{-2}\cdot[-\sin(\pi x)]\cdot\pi\\\\=\dfrac{\pi\sin(\pi x)}{[\cos(\pi x)]^2}=\pi\dfrac{\sin(\pi x)}{\cos(\pi x)}\cdot\dfrac{1}{\cos(\pi x)}\\\\=\pi\tan(\pi x)\sec(\pi x)

6 0
3 years ago
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