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zhenek [66]
3 years ago
11

1. What is the supplement of an angle measuring 35°? 2. What is the complement of an angle measuring 70°?

Mathematics
1 answer:
bixtya [17]3 years ago
4 0

Answer: Q1.=145, Q2.=20

Step-by-step explanation:

two supplementary angles equal 180

1. 180-35=145

2 . complementary angles , both add up to 90

90-70=20

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zavuch27 [327]
If AC=BD, than Quad ABCD is a rectangle
AC
√(3+3)²+(6-1)²
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Quad ABCD is not a rectangle because √61 and √29 are not equal.
7 0
3 years ago
GIVING BRAINLIEST
Umnica [9.8K]

Answer:

140

Step-by-step explanation:

180 - 40 = 140

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Sam needs a web designer. Designer A is offering her services for an initial $550 in addition to $105 per hour. Designer B is of
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After two hours the prices will meet a 760

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Determine whether the graph represents a function. Explain.
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Complete the given diagram by dragging expressions to each leg of the triangle. Then, correctly complete the equation to derive
Nimfa-mama [501]

The equation to derive the distance d is \sqrt{(x2-x1)^2+(y2-y1)^2}. The lengths of the other legs of the given triangle are (y2 - y1) and (x2 - x1).

<h3>What is the formula for calculating the distance between two points?</h3>

Consider the two points (x1, y1) and (x2, y2)

The formula used for calculating the distance between the two points is

distance = \sqrt{(x2-x1)^2+(y2-y1)^2}

<h3>Calculation:</h3>

Given that,

The triangle in the graph has vertices (x1, y1), (x2, y2), and (x2, y1)

Since this triangle makes 90°, it is a right-angled triangle.

Hypotenuse = (x1, y1) to (x2, y2), Adjacent = (x1, y1) to (x2,y1), and Opposite = (x2, y1) to (x2, y2).

Consider the length of the hypotenuse = d

So, using the distance formula, the length of the hypotenuse(d) is,

d = \sqrt{(x2-x1)^2+(y2-y1)^2}

And the lengths of the other two legs of the given triangle are,

Length of the adjacent side: (x1, y1) to (x2,y1)

= \sqrt{(x2-x1)^2+(y1-y1)^2}

= \sqrt{(x2-x1)^2+0}

= (x2-x1)

Length of the opposite side: (x2, y1) to (x2, y2)

= \sqrt{(x2-x2)^2+(y2-y1)^2}

= \sqrt{0+(y2-y1)^2}

= (y2-y1)

Therefore, the derived distances for the given triangle are:

d=\sqrt{(x2-x1)^2+(y2-y1)^2}, (x2 - x1), and (y2 - y1).

Learn more about the distance between two points here:

brainly.com/question/661229

#SPJ1

4 0
2 years ago
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