Answer: There are 16 vans and 36 buses and Option 'c' is correct.
Step-by-step explanation:
Since we have given that
For high school A,
Number of vans = 5
Number of buses = 3
Number of students = 188
For high school B,
Number of vans = 10
Number of buses = 5
Number of students = 340
So, Let the number of students in van be 'x'
Let the number of students in bus be 'y'.
According to question, it becomes;
![5x+3y=188-----------------(1)\\\\10x+5y=340-------------------(2)](https://tex.z-dn.net/?f=5x%2B3y%3D188-----------------%281%29%5C%5C%5C%5C10x%2B5y%3D340-------------------%282%29)
So, first we do:
2(5x+3y=188)
10x+6y=376----------------(3)
So, from (2) and (3), we get that
![10x+6y=376\\\\10x+5y=340\\\\------------------------------\\\\y=36](https://tex.z-dn.net/?f=10x%2B6y%3D376%5C%5C%5C%5C10x%2B5y%3D340%5C%5C%5C%5C------------------------------%5C%5C%5C%5Cy%3D36)
so, put the value of y = 36 in the eq(1), we get that
![5x+3\times 36=188\\\\5x+108=188\\\\5x=188-108\\\\5x=80\\\\x=16](https://tex.z-dn.net/?f=5x%2B3%5Ctimes%2036%3D188%5C%5C%5C%5C5x%2B108%3D188%5C%5C%5C%5C5x%3D188-108%5C%5C%5C%5C5x%3D80%5C%5C%5C%5Cx%3D16)
Hence, there are 16 vans and 36 buses and Option 'c' is correct.