Answer:
<u>C) −12/5⋅(7/12⋅1/9)⋅8/5=(−12/5⋅7/12)⋅(1/9⋅8/5)</u>
2/3 is basically 0.6666666667 which is the same as 66% so any percentage bigger than 66% such as 75% (0.75) which is 3/4 (as a fraction) is bigger than 2/3
<span>a) Differentiate both sides of lnq − 3lnp + 0.003p=7 with respect to p, keeping in mind that q is a function of p and so using the Chain Rule to differentiate any functions of q:
(1/q)(dq/dp) − 3/p + 0.003 = 0
dq/dp = (3/p − 0.003)q.
So E(p) = dq/dp (p/q) = (3/p − 0.003)(q)(p/q) = (3/p − 0.003)p = 3 − 0.003p.
b) The revenue is pq.
Note that (d/dp) of pq = q + p dq/dp = q[1 + dq/dp (p/q)] = q(1 + E(p)), which is zero when E(p) = −1. Therefore, to maximize revenue, set E(p) = −1:
3 − 0.003p = −1
0.003p = 4
p = 4/0.003 = 4000/3 = 1333.33</span>
-2y-4=4y-4
2) cancel 4 out on both sides
-2y=4y
3) divide both sides by -2
y=-2y
4) subtract both sides by -2y
y+2y=0
5)3y=0
6) divide by 3
Y=0
Answer:
Therefore, Company B is offering the lowest price/lb at $12.73/lb.
So, Company A's price / lb = ($32.50/2.5lbs) = $13.00/lb
Step-by-step explanation:
To determine price per lb, divide dollar amount by lbs.
- Company A sells 2 1/2lbs (2.5lbs) for $32.50
- Company B sells 2 3/4lbs (2.75lbs) for $35.00
And, Company B's price / lb = ($35.00/2.75lbs) = $12.73/lb
