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AleksAgata [21]
3 years ago
14

Help much appreciated ):

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
7 0

Answer

Step-by-step explanation:

help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):help much appreciated ):    hope this helps leave a heart c:

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Ms. Drohan's dog weighs 11 pounds 8 ounces. Ms. Granahan's dog weighs 245 ounces. Whose dog weighs more? A.
mash [69]

Answer: B . Ms. Granahan's dog weighs more

Step-by-step explanation:

1 pound = 16 ounces

11 pounds x 16 ounces = 176 ounces

176 + 8 ounces = 184 ounces

therefore , Ms. Drohan's dog weighs 185 ounces

B is the answer.

7 0
3 years ago
Read 2 more answers
Please answer it now
FrozenT [24]

Answer:

x = 19

Step-by-step explanation:

The angles of a triangle add to 180

U and S are equal since they are the base angles  and UT and ST are equal

S + T + U = 180

x + 26 + 90 + x+26 = 180

Combine like terms

2x +142 = 180

Subtract 142 from each side

2x = 38

Divide each side by 2

2x/2 = 38/2

x = 19

8 0
3 years ago
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It's solving multi-step inequalities
babymother [125]
H is less than or equal to 35

Just simplify each side and solve for the variable. 
4 0
3 years ago
What is the third quartile, Q3, of the following distribution?
GREYUIT [131]

Answer:

The third quartile is:

Q_3=29

Step-by-step explanation:

First organize the data from lowest to highest

4, 5, 10, 12, 14, 16, 18, 20, 21, 21, 22, 22, 24, 26, 29, 29, 33, 34, 43, 44

Notice that we have a quantity of n = 20 data

Use the following formula to calculate the third quartile Q_3

For a set of n data organized in the form:

x_1, x_2, x_3, ..., x_n

The third quartile is  Q_3:

Q_3=x_{\frac{3}{4}(n+1)}

With n=20

Q_3=x_{\frac{3}{4}(20+1)}

Q_3=x_{15.75}

The third quartile is between x_{15}=29 and x_{16}=29

Then

Q_3 =x_{15} + 0.75*(x_{16}- x_{15})

Q_3 =29 + 0.75*(29- 29)\\\\Q_3 =29

5 0
3 years ago
Read 2 more answers
8. Show work<br> here for<br> 5(3d+5e+3)
Darya [45]

Answer:

15d+25e+15

Step-by-step explanation:

Distribute

4 0
3 years ago
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