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UNO [17]
4 years ago
12

Sleep deprivation, CA vs. OR, Part I. According to a report on sleep deprivation by the Centers for Disease Control and Preventi

on, the proportion of California residents who reported insufficient rest or sleep during each of the preceding 30 days is 8.0%, while this proportion is 8.8% for Oregon residents. These data are based on simple random samples of 11,545 California and 4,691 Oregon residents. Calculate a 95% confidence interval for the difference between the proportions of Californians and Oregonians who are sleep deprived and interpret it in context of the data.
Mathematics
1 answer:
vlabodo [156]4 years ago
7 0

Answer:

0.008±0.0095=(-0.0015,0.0175)

Step-by-step explanation:

In this case we must use the formula to calculate the confidence interval for the difference between two proportions given by inferential statistics. The formula to calculate both limits of the interval is as it follows:

(p_{1}-p_{2} )+\sqrt[]{\frac{p_{1}(1-p_{1})}{n_{1} }+\frac{p_{2}(1-p_{2})}{n_{2}}  } \\(p_{1}-p_{2} )-\sqrt[]{\frac{p_{1}(1-p_{1})}{n_{1} }+\frac{p_{2}(1-p_{2})}{n_{2}}  }

Where:

p_{1}: proportion of population one (in our case: Oregon residents who reported insufficient rest or sleep)

p_{2}: proportion of population two (in our case: California residents who reported insufficient rest or sleep)

z_{(∝/2)}: quantile of the normal distribution with α/2 probability (in our case, from the standard normal table we have 1.96 for a confidence level of 95%)

n_{1}: sample size for population one (in our case, sample of Oregon residents)

n_{2}: sample size for population two (in our case, sample of California residents)

Now, with our data we have:

p_{1}=0.088  

p_{2}=0.08  

z_{(∝/2)}=1.96  

n_{1}=4,691  

n_{2}=11,545  

Therefore, we obtain:

(0.088-0.08)+1.96\sqrt{\frac{0.088(1-0.088)}{4,691}+\frac{0.08(1-0.08)}{11,545} } \\(0.088-0.08)-1.96\sqrt{\frac{0.088(1-0.088)}{4,691}+\frac{0.08(1-0.08)}{11,545} }

Finally, the result for our interval:

0.008+0.0095=(-0.0015,0.0175)

According to the result we can say with a 95% confidence, that the proportion of Oregon residents with sleep deprivation issues is the same as the proportion of California residents. The reason for this is that 0 (zero) is contained within the interval.

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a) P(X>8)=P(\frac{X-\mu}{\sigma}>\frac{8-\mu}{\sigma})=P(Z>\frac{8-7.6}{0.4})=P(Z>1)

And we can find this probability using the complement rule and the standard normal table or excel:

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And we can find this probability using the standard normal table or excel:

P(Z

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the amount of soft frink of a population, and for this case we know the distribution for X is given by:

X \sim N(7.6,0.4)  

Where \mu=7.6 and \sigma=0.4

We are interested on this probability

P(X>8)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>8)=P(\frac{X-\mu}{\sigma}>\frac{8-\mu}{\sigma})=P(Z>\frac{8-7.6}{0.4})=P(Z>1)

And we can find this probability using the complement rule and the standard normal table or excel:

P(Z>1)=1-P(Z

Part b

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the standard normal table or excel:

P(Z

Part c

For this case we have a total of 868 cups and we know that the fraction of cups that will be overflow is 0.159, so then the expected number of cups overflow would be:

N = 868*0.159= 138.012 \approx 138

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4 years ago
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