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3 years ago

Hola guys...Can you plz help me to find the solutions for -3x+y=0 for linear equations in two variables graph... Pleaseee

Mathematics

1 answer:

S_A_V [24]3 years ago

3 0

(-1.5,-3) (-1,-2) (-.5,-1) (0,0) (.5,1) (1,2) (1.5,3)

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Show that 155 can be express as the sum of a power of 2 and a cube number?

son4ous [18]

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3 years ago

Help! Geometry Triangle Congruence

Feliz [49]

Answer:

Step-by-step explanation:

Thank your for revising and improving the image.

Assuming DF is a straight line,

Given E is the mid-point of DF

mCE = mGF

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Then

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2 years ago

Which of the following are some of the possible soulitions for the inequality -9w < -54

Alekssandra [29.7K]

the answer

w < 6

Step by Step

-9w < -54

w < -54/-9

w< 6

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3 years ago

Reduced form of 2ab^2-a^2 b^2/5

Ket [755]

Answer:

$2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}$

Step-by-step explanation:

Given the expression

$2ab^2-\frac{a^2b^2}{5}$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:2ab^2=\frac{2ab^25}{5}$

$2ab^2-\frac{a^2b^2}{5}=\frac{2ab^2\cdot \:5}{5}-\frac{a^2b^2}{5}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{2ab^2\cdot \:5-a^2b^2}{5}$

$=\frac{10ab^2-a^2b^2}{5}$

Thus,

$2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}$

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2 years ago

What is the place value of 8 in 281480100

laiz [17]

The number 8 is in Ten thousand space

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3 years ago

Read 2 more answers