Question

(3x+2)^2- (3x+1)(3x-5)

Answer 1

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

$\tt{ \left(3x+2 \right) }^{ 2 } -(3x+1)(3x-5)$

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\tt{ \left(3x+2 \right) }^{ 2 } -(3x+1)(3x-5)$

Use binomial theorem $\tt\left(a+b\right)^{2}=a^{2}+2ab+b^{2}$ to expand $\tt\left(3x+2\right)^{2}$.

$\tt \: 9x^{2}+12x+4-\left(3x+1\right)\left(3x-5\right)$

Use the distributive property to multiply 3x+1 by 3x-5 and combine like terms.

$\tt \: 9x^{2}+12x+4-\left(9x^{2}-12x-5\right)$

To find the opposite of 9x²-12x-5, find the opposite of each term.

$\tt \: 9x^{2}+12x+4-9x^{2}+12x+5$

Cancel 9x² and -9x² to get 0.

$\tt \: 12x+4+12x+5$

Combine 12x and 12x to get 24x.

$\tt \: 24x+4+5$

Add 4 and 5 to get 9.

$= \boxed{\boxed{ \bf \: 24x + 9}}$