Hello,
y=2xe^x
y'=2(e^x+xe^x)=2(x+1)e^x
y''=2(e^x+(x+1)e^x)=2(x+2)e^x
x |-infinite -2 0 +infinite
e^x | ++++++++++++++++++
x+2 |------------0 +++++++++++
y'' | -----------0 +++++++++++
y''<0 if x<-2
<span>The interval on which the graph is concave down is (-infinite -2[</span>
Depends on the fraction to determine your answer
Knowing that there are two logs on both sides of the brackets, they cancel out.
This leaves:
4y-1=2y+7 (solve for y)
4y-2y=7-1
2y=6
y=3
Hope this helped :)
Answer:
Hey there! here's your answer
Step-by-step explanation:
Speed = distance/Time
Speed = 3/5 ÷ 1/2
Speed = 3/5 * 2
Speed = 6/5 mph or 1.2 mph.
