Question

Find a numerical value of one trigonometric function of x for cos^2x+ 2sin x-2=0

Answer 1

Answer:

x = 90°

Step-by-step explanation:

We are given a trigonometric function of x from which we have to a solution for x.

The function is $\cos^{2} x + 2\sin x - 2 = 0$

⇒ $1 - \sin^{2} x + 2\sin x - 2 = 0$  

{Since we know the identity $\sin^{2} \alpha + \cos^{2} \alpha = 1$}

⇒ $\sin^{2} x - 2 \sin x + 1 = 0$

⇒ $(\sin x - 1)^{2} = 0$

{Since we know the formula (a - b)² = a² - 2ab + b²}

⇒ $(\sin x - 1) = 0$

⇒ $\sin x = 1 = \sin 90$

⇒ x = 90° (Answer)

Answer 2

Answer:

c on edge

Step-by-step explanation:

idk what the guy above was doing