Answer:
Step-by-step explanation:
this is confusing b/c they are asking about two trains traveling at differnt speeds, but.. if you put the speeds together and make one train... imaginary.. ofc... traveling at the speed of both trains combined... when will it be 50 miles from the station?
maybe you can solve that? I'll solve it below.. but.. if you can.. try it now, on your own
below is my answer... don't look until you have solved yours :P
80+70= 150kph
when will this have traveled 50Km?
you may be able to see that it will take 1/3 of an hour to travel 50 km
so 60 minutes times 1/3 = 20 minutes :)
Answer:
10 quarters, 23 dimes
Step-by-step explanation:
Make dimes = d and quarters = q. Let the number of dimes and quarters add up to 33 and the value of the dimes and quarters add up to 4.80. The system of equations should look like:
- d + q = 33
- 0.10d + 0.25q = 4.80
Solve for d in the first equation. Subtract q from both sides.
d = 33 - q
Substitute d into the second equation.
0.10(33 - q) + 0.25q = 4.80
Distribute 0.10 inside the parentheses.
3.3 - 0.10q + 0.25q = 4.80
Combine like terms.
3.3 + 0.15q = 4.80
Subtract 3.3 from both sides.
0.15q = 1.5
Divide both sides by 0.15.
q = 10
Substitute this value of q into where we solved for d (d = 33 - q).
d = 33 - (10)
d = 23
For solving steps use photomath
I am fairly certain it is C
Answer:
X+Y =23
X-Y =7
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