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3 years ago

Given f(x)=x2, g(x)=x+6, h(x)=7 find f{g[h(x)]}.

Mathematics

1 answer:

gogolik [260]3 years ago

4 0

Answer:

169

Step-by-step explanation:

$f(g(h(x))) = \\f(g(7)) =\\f(7+6) = \\(7+6)^2= 169$

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A clown bought six bags of round balloons with twenty four ballons in each bag . The clown also bought three bags of long balloo

Makovka662 [10]

Answer:

144 round balloons and 108 long balloons

Step-by-step explanation:

6 times 24 = 144

3 times 36 = 108

7 0

4 years ago

2(x+6)<10 solve for x and inequality

Crazy boy [7]

Answer:

x<-1

Step-by-step explanation:

2(x+6)<10

Distribute 2x+12<10

Subtract 12 2x<-2

Divide 2 x<-1

4 0

3 years ago

Which quadrilateral's diagonals are congruent and perpendicular bisectors of each other?

AnnyKZ [126]

Diagonals congruent: rectangle, square, isosceles trapezoid

Perpendicular bisectors: Rhombus, Square

3 0

3 years ago

A jewelry box is designed such that its length is twice its width and its depth is 2 inches less than its width the volume of th

Sedaia [141]

Answer:

$Volume = 2x^{3}-4x^{2}$

Step-by-step explanation:

Let x be the width of the jewellery box

Given:

Length of the box is twice its width

Length of the box = $2\times width$

Length of the box = $2\times x= 2x$

depth of the box is equal to 2 inches less than its width.

depth of the box = $width-2$

depth of the box = $x-2$

The volume of the box is 64 inches.

Solution:

We know that the formula of the volume is.

$Volume = length\times width\times depth$

Now we substitute all known value in above.

$Volume = 2x\times x\times (x-2)$

$Volume = 2x^{2}(x-2)$

$Volume = 2x^{3}-4x^{2}$

Therefore, the equation of the volume of the box is.

$Volume = 2x^{3}-4x^{2}$

5 0

3 years ago

How many different groups of students can show up for a seminar with an enrollment of 11?

Valentin [98]

For this question, will we use permutations.

So, how many people can be in the first group? 11. Then what about the second group? Well because there is already at least one person in the slot for the group it must 10. Then so on.

Then we multiply all of the terms.

11*10*9*8*7*6*5*4*3*2*1 or 11! Which means the same thing.

11! = <span>39916800
</span>
There are <span>39916800 ways to make a group.</span>

7 0

4 years ago