Answer:
By the Central Limit Theorem, both would be approximately normal and have the same mean. The difference is in the standard deviation, since as the sample size increases, the standard deviation decreases. So the SRS of 600 would have a smaller standard deviation than the SRS of 200.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean 
and standard deviation 
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation 
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For the sampling distribution of size n of a sample proportion p, the mean is p and the standard deviation is 
Differences between SRS of 200 and of 600
By the Central Limit Theorem, both would be approximately normal and have the same mean. The difference is in the standard deviation, since as the sample size increases, the standard deviation decreases. So the SRS of 600 would have a smaller standard deviation than the SRS of 200.
Answer: 20
Step-by-step explanation:
Since Line l is a segment bisector, we know that AM and MC are equal to each other.
6y-4=2y+12 [subtract both sides by 2y]
4y-4=12 [add both sides by 4]
4y=16 [divide both sides by 4]
y=4
Now that we have y, we plug that into AM.
6(4)-4 [multiply]
24-4 [subtract]
20
Now, we know that AM is 20.
?????? Is there a picture? I can’t see it if there is :)
9514 1404 393
Answer:
a) BE = 5; DE = 6; EF = 4
b) ∠EFC ≅ ∠DA.F ≅ ∠BDE or <em>b = e = f = i</em>
Step-by-step explanation:
Each short segment is the same length as the marked one it is parallel to.
E is the midpoint of BC, so BE = EC = 5.
ADEF is a parallelogram, so DE = A.F = 6.
D is the midpoint of AB, so AD = DB = 4. ADEF is a parallelogram, so ...
EF = AD = 4
__
As we have noted, AB║EF and DE║A.F, so corresponding angles and alternate interior angles are congruent. <em>b = e = f = i</em>
The second one is the function
