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inn [45]
3 years ago
15

Solve for x x^2 - 2x - 35 = 0x

Mathematics
1 answer:
olga_2 [115]3 years ago
4 0

Answer:

 x = 7

 x = -5

Step-by-step explanation:

Given

x² - 2x - 35 = 0

Consider the factors of the constant term (- 35) which sum to give the coefficient of the x- term (- 2)

The factors are - 7 and + 5, since

- 7 × 5 = - 35 and - 7 + 5 = - 2, thus

(x - 7)(x + 5) = 0

Equate each factor to zero and solve for x

x + 5 = 0 ⇒ x = - 5

x - 7 = 0 ⇒ x = 7

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wel

heres a key for then

SIN= O/H

COS= A/H

TAN= O/A

CSC= H/O

SEC= H/A

COT= A/O

let me know if u have anymore questions

Answer:

3/5 is ur answer

Step-by-step explanation:

ok so its SIN

SIN is o/h (o= opposite and h= hypotenuse)

so we can look at the picture and it says find the SIN of a

ok so the O would be 3 and the H would be 5

so ur answer would be 3/5

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Answer:

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Step-by-step explanation:

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