Answer: the statements and resons, from the given bench, that fill in the blank are shown in italic and bold in this table:
Statement Reason
1. K is the midpoint of segment JL Given
2. segment JK ≅ segment KL <em>Definition of midpoint</em>
3. <em>L is the midpoint of segment KM</em> Given
4. <em>segment KL ≅ segment LM</em> Definition of midpoint
5. segment JK ≅ segment LM Transitive Property of
Congruence
Explanation:
1. First blank: you must indicate the reason of the statement "segment JK ≅ segment KL". Since you it is given that K is the midpoint of segment JL, the statement follows from the very <em>Definition of midpoint</em>.
2. Second blank: you must add a given statement. The other given statement is <em>segment KL ≅ segment LM</em> .
3. Third blank: you must indicate the statement that corresponds to the definition of midpoint. That is <em>segment KL ≅ segment LM</em> .
4. Fourth and fith blanks: you must indicate the statement and reason necessary to conclude with the proof. Since, you have already proved that segment JK ≅ segment KL and segment KL ≅ segment LM it is by the transitive property of congruence that segment JK ≅ segment LM.
Answer:
C. 14 metres cubed
Step-by-step explanation:
The volume of a sphere is denoted by: 
, where r is the radius, while the volume of a cylinder is denoted by: 
, where r is the radius and h is the height.
Here, we know that the sphere and cylinder have the same radius and height. However, the "height" of the sphere is technically just the diameter, which is twice the radius. So, h = 2r. We know the volume of the cylinder is 21, so:
πr³ = 21/2 = 10.5
Now plug this into the volume of a sphere formula:
The answer is C, 14 metres cubed.
The area is equal to 60 square units
Simple, just divide the number by the percentage and you get the original number. You can check it by multiplying the original number of 272 by 55% or .55 to get 150.
150/.55 = 272
