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SpyIntel [72]
3 years ago
13

Write the equation of the parabola in vertex form.Vertex: (−4,6); Point: (−2,−2)

Mathematics
1 answer:
gtnhenbr [62]3 years ago
5 0

Answer:

y = - 2(x + 4)² + 6

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k ) = (- 4, 6 ) , thus

y = a(x - (- 4) )² + 6 , that is

y = a(x + 4)² + 6

To find a substitute (- 2, - 2) into the equation

- 2 = a(- 2 + 4)² + 6 ( subtract 6 from both sides )

- 8 = a(2)² = 4a ( divide both sides by 4 )

- 2 = a , thus

y = - 2(x + 4)² + 6 ← equation in vertex form

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I need help figuring out what I did wrong
rewona [7]

Answer:

D

Step-by-step explanation:

Using the addition formula for sine

sin(a + b) = sinacosb + cosasinb

and the exact values

sin(\frac{\pi }{4} ) = cos(\frac{\pi }{4} ) = \frac{\sqrt{2} }{2} , cos(\frac{\pi }{6}) = \frac{\sqrt{3} }{2} , sin(\frac{\pi }{6}) = \frac{1}{2}

Note that \frac{5\pi }{12} = \frac{\pi }{4} + \frac{\pi }{6} , thus

sin(\frac{5\pi }{12})

= sin(\frac{\pi }{4} + \frac{\pi }{6} )

= sin(\frac{\pi }{4})cos(\frac{\pi }{6} ) + cos(\frac{\pi }{4})sin(\frac{\pi }{6})

= ( \frac{\sqrt{2} }{2} × \frac{\sqrt{3} }{2} ) + ( \frac{\sqrt{2} }{2} × \frac{1}{2} )

= \frac{\sqrt{6} }{4} + \frac{\sqrt{2} }{4}

= \frac{\sqrt{6}+\sqrt{2}  }{4} → D

4 0
3 years ago
Read 2 more answers
Will give brainliest
ehidna [41]

Answer:

25.047 or roughly 25.

Step-by-step explanation:

I solved it wrong the first time then i double check with wolframalpha and got the correct number.

We know that the area of the tile is 18 \sqrt{3} and it makes a triangle, we also know the base and height. In this case the base is 2\sqrt{3}^{x/12} and the height is also given which is \sqrt{3}^{\frac{x}{6} }.

Area of triangle = \frac{bh}{2},

substituting we will end up with  18 \sqrt{3}  =( 2\sqrt{3}^{x/12}  *  \sqrt{3}^{\frac{x}{6} }) / 2

Here is the tricky part \sqrt{x} = x^{\frac{1}{2} }, i totally forgot about that lol.

Simplifying: we will get  18 \sqrt{3} = 3^{\frac{x}{8} }

Now, in order to find the x, we will need to take the log of both sides.

log18\sqrt{3}  = \frac{x}{8} log3

Solving for x we end up getting:

8\frac{log18\sqrt{3} }{log3} = x

where x = 25.047.

To be honest I deserve a nobel prize not a brainliest lol.

Good question bro, take it easy.

5 0
3 years ago
What value of n makes each statement true, pls include work
sammy [17]

Answer:

1. n=2

2. n=12

3. n=2

Step-by-step explanation:

1

12xy³/4xⁿy=3y²/x

12x²y³=12y³xⁿ (cross multiplied)

x²=xⁿ (cancelled out (12y³))

2=n

2

(-3a/2b⁴)³=-27a³/8bⁿ

-27a³/8b¹²=-27a³/8bⁿ (cubed left side)

-216a³bⁿ =-216a³b¹² (cross multiplied)

bⁿ=b¹² (cancelled out (-216a³))

n=12

3

(xy⁶/x⁵yⁿ)²=y⁸/x⁸

x²y¹²/x¹⁰y²ⁿ=y⁸/x⁸ (squared left side)

x²y¹²/x¹⁰y²yⁿ=y⁸/x⁸

y¹⁰/x⁸yⁿ=y⁸/x⁸ (simplified)

y¹⁰x⁸=x⁸yⁿy⁸ (cross multiplied)

y²=yⁿ (cancelled out (x⁸), simplified)

n=2

6 0
3 years ago
Solve for x: <br> 4(x + 2) = 3(x - 2)
Pani-rosa [81]

Answer:

x = -14

Step-by-step explanation:

Step 1: Write equation

4(x + 2) = 3(x - 2)

Step 2: Solve for <em>x</em>

  1. Distribute: 4x + 8 = 3x - 6
  2. Subtract 3x on both sides: x + 8 = -6
  3. Subtract 8 on both sides: x = -14

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

4(-14 + 2) = 3(-14 - 2)

4(-12) = 3(-16)

-48 = -48

7 0
3 years ago
Read 2 more answers
In △ABC, point P∈
Minchanka [31]
<h3>Answer:</h3>

56 m²

<h3>Explanation:</h3>

A diagram can be helpful.

Triangles with the same altitude will have areas proportional to the length of their bases.

The altitude from B to PC is the same for triangles BMP and BMC, so they have areas that are in the same proportion as MP : MC. Since M is the midpoint of CP, MP = MC and ABMP = ABMC = 21 m². Then ...

... ACPB = 21 m² + 21 m² = 42 m²

The altitude from C to AB is the same for triangles CPA and CPB, so those triangles have areas in the sampe proportion as AP : BP = 1 : 3. Then ...

... ACPA : ACPB = PA : PB = 1 : 3

... ACPA : 42 m² = 1 : 3

So, the area of ∆CPA is 1/3 of 42 m², or 14 m². The area of ABC is the sum of the areas of CPA and CPB, so is ...

... AABC = ACPA + ACPB = 14 m² + 42 m²

... AABC = 56 m²

6 0
3 years ago
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