Answer:
25.047 or roughly 25.
Step-by-step explanation:
I solved it wrong the first time then i double check with wolframalpha and got the correct number.
We know that the area of the tile is 18
and it makes a triangle, we also know the base and height. In this case the base is 2
and the height is also given which is
.
Area of triangle =
,
substituting we will end up with 18
=( 2
*
) / 2
Here is the tricky part
, i totally forgot about that lol.
Simplifying: we will get 18
= 
Now, in order to find the x, we will need to take the log of both sides.

Solving for x we end up getting:
= x
where x = 25.047.
To be honest I deserve a nobel prize not a brainliest lol.
Good question bro, take it easy.
Answer:
1. n=2
2. n=12
3. n=2
Step-by-step explanation:
1
12xy³/4xⁿy=3y²/x
12x²y³=12y³xⁿ (cross multiplied)
x²=xⁿ (cancelled out (12y³))
2=n
2
(-3a/2b⁴)³=-27a³/8bⁿ
-27a³/8b¹²=-27a³/8bⁿ (cubed left side)
-216a³bⁿ =-216a³b¹² (cross multiplied)
bⁿ=b¹² (cancelled out (-216a³))
n=12
3
(xy⁶/x⁵yⁿ)²=y⁸/x⁸
x²y¹²/x¹⁰y²ⁿ=y⁸/x⁸ (squared left side)
x²y¹²/x¹⁰y²yⁿ=y⁸/x⁸
y¹⁰/x⁸yⁿ=y⁸/x⁸ (simplified)
y¹⁰x⁸=x⁸yⁿy⁸ (cross multiplied)
y²=yⁿ (cancelled out (x⁸), simplified)
n=2
Answer:
x = -14
Step-by-step explanation:
Step 1: Write equation
4(x + 2) = 3(x - 2)
Step 2: Solve for <em>x</em>
- Distribute: 4x + 8 = 3x - 6
- Subtract 3x on both sides: x + 8 = -6
- Subtract 8 on both sides: x = -14
Step 3: Check
<em>Plug in x to verify it's a solution.</em>
4(-14 + 2) = 3(-14 - 2)
4(-12) = 3(-16)
-48 = -48
<h3>Answer:</h3>
56 m²
<h3>Explanation:</h3>
A diagram can be helpful.
Triangles with the same altitude will have areas proportional to the length of their bases.
The altitude from B to PC is the same for triangles BMP and BMC, so they have areas that are in the same proportion as MP : MC. Since M is the midpoint of CP, MP = MC and ABMP = ABMC = 21 m². Then ...
... ACPB = 21 m² + 21 m² = 42 m²
The altitude from C to AB is the same for triangles CPA and CPB, so those triangles have areas in the sampe proportion as AP : BP = 1 : 3. Then ...
... ACPA : ACPB = PA : PB = 1 : 3
... ACPA : 42 m² = 1 : 3
So, the area of ∆CPA is 1/3 of 42 m², or 14 m². The area of ABC is the sum of the areas of CPA and CPB, so is ...
... AABC = ACPA + ACPB = 14 m² + 42 m²
... AABC = 56 m²