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Sauron [17]
2 years ago
13

The account balance on April 1st is $50.51. On April 15th, a payment of $15.00 is made. On April 25th, a purchase of $19.27 is m

ade. What is the finance charge if the annual rate is 18%? What is the new account balance?
Mathematics
2 answers:
Ilia_Sergeevich [38]2 years ago
4 0

Answer:

Step-by-step explanation:

Combine the information in the problem and the chart using the average balance method to solve the problem.

The account balance on April 1st is $50.51. On April 15th, a payment of $15.00 is made. What is the average daily balance for the account? What is the finance charge if the annual rate is 18%? What is the new account balance?

matrenka [14]2 years ago
3 0
Hi there!

The true answer is as follows:

Finance charge = $0.76
To get this you need to take the account balance on April 1st and multiply by the annual rate of 18%, which looks like this:

$50.51 × 0.18 = 9.0918
Then you divide your answer by 12 for the months of the year to get:

9.0918 ÷ 12 = 0.75765
Which rounds to $0.76 for you finance charge

New balance = $55.54
To get this you take the account balance on April 1st and subtract the payment of $15.00 and then add the purchase of $19.27 and the finance charge of $0.76, like so:

$50.51 - $15.00 = $35.51 + $19.27 + $0.76 = $55.54

Your friend, ASIAX
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Step-by-step explanation:

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Answer:

ME=1.96\sqrt{\frac{0.47 (1-0.47)}{800}}=0.0346  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

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Solution to the problem

We assume for this case a confidence level of 95%. In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

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The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And if we replace the values obtained we got this:

ME=1.96\sqrt{\frac{0.47 (1-0.47)}{800}}=0.0346  

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