Part A)
Given
Using the point-slope form of the line equation
where
m is the slope of the line
(x₁, y₁) is the point
In our case:
substituting the values m = 6 and the point (x₁, y₁) = (7, 2) in the point-slope form of the line equation
Therefore, the equation in point-slope form for the line having the slope m = 6 and containing the points (7,2) will be:
Part B)
Given
Using the point-slope form of the line equation
where
m is the slope of the line
(x₁, y₁) is the point
In our case:
substituting the values m = -3 and the point (x₁, y₁) = (3, 8) in the point-slope form of the line equation
Therefore, the equation in point-slope form for the line having the slope m = -3 and containing the points (3, 8) will be:
Answer:
option D
Step-by-step explanation:
take 39 degree as reference angle
using cos rule
cos 39 = adjacent / hypotenuse
0.77 = x / 7
x = 7*0.77
x = 5.39
x = 5.4
ΔABC is a 45 - 45 - 90 triangle. The pattern of its sides is as follows:
Each leg = 1 unit (and both legs are that way, since the triangle is isosceles - so two sides are the same)
Hypotenuse = √2 units.
So if we know either leg, we multiply by √2 to get the hypotenuse. In reverse, we divide by √2 if we know the hypotenuse to get the measurement of a leg.
Our problem tells us that the hypotenuse AC is 10 units. We divide 10 by √2 to get the measurement of leg AB. Since it's a 45 -45 - 90 triangle, AB = BC.
to rationalize the radical
Thus, each leg is 5\sqrt{2} [/tex].
X - the number of loads by land carriers,
y - the number of loads by air carriers;
The system of inequalities:
x + y ≤ 150
2,000 x + 1,250 y ≤ 180,000
Step-by-step explanation:
I have attached the graph of the question. So this is the graph of the question and i also attached the solved question screen shot.
I hope you get the idea. Thanks
