3 years ago

(3 2/3 +1 1/4 )·(1− 47/59 )

Mathematics

1 answer:

Naddik [55]3 years ago

5 0

Answer:

I got 1 sorry if it's wrong

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Does this graph show a function? Explain how you know.

Bess [88]

Answer:

a. no the graph fails the vertical line test

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3 years ago

Read 2 more answers

Alex sold 330 candy bars, milk chocolate candy bars sold for $2 each and white chocolate candy bars sold for $3 each. Alex sold

Alinara [238K]

Answer:

<em>Alex sold 330 white chocolate bars</em>

Step-by-step explanation:

let the milk chocolate candy be x and the white chocolate candy be y. then

then 2x+3y=990----1)

x+y=330-----2)

from eq 2) ⇒ x=330-y---------3)

Putting eq 3 in eq 1

2(330-y) +3y=990

660-2y+3y=990

y=990-660=330-----------4)

Putting eq4 in eq1

2x+3(330)=990

2x+990=990

2x=990-990

2x=0

x=0---------------------------5)

4 0

3 years ago

Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).

Oduvanchick [21]

For two complex numbers $z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)$ and $z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)$ , the product is

$z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))$

That is, you multiply the moduli and add the arguments. You have $z_1=7e^{i40^\circ}$ and $z_2=6e^{i145^\circ}$ , so the product is

$z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}$