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olga nikolaevna [1]
3 years ago
6

The gas mileage of an SUV is 15.25 Miles per gallon. The gas mileage of a car is 26.4 Miles per gallon. How much farther will th

e car travel if both vehicles use 12.5 gallons of gas?
Mathematics
2 answers:
Lelechka [254]3 years ago
4 0
15.25m/1gallon=Xm/12.5gallons so the SUV will travel 190.625m

The car will travel 330m

330-190.625=139.375 more miles
Oxana [17]3 years ago
3 0

Answer:

Car will travel 139.375 miles extra compared to SUV using 12.5 gallons of gas.

Step-by-step explanation:

The gas mileage of an SUV is 15.25 Miles per gallon.

Mileage of SUV = 15.25 Miles per gallon

The gas mileage of a car is 26.4 Miles per gallon

Mileage of car = 26.4 Miles per gallon

We need to find how much farther will the car travel if both vehicles use 12.5 gallons of gas,

Distance traveled by car using 12.5 gallon gas = Mileage x Volume of gas

Distance traveled by car using 12.5 gallon gas = 12.5 x 26.4 = 330 miles

Distance traveled by SUV using 12.5 gallon gas = Mileage x Volume of gas

Distance traveled by SUV using 12.5 gallon gas = 12.5 x 15.25 = 190.625 miles

Extra distance traveled by car = 330 - 190.625 = 139.375 miles

Car will travel 139.375 miles extra compared to SUV using 12.5 gallons of gas.

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What mathematicians helped to discover alternatives to euclidean geometry in the nineteenth century
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Answer:

Nikolai Lobachevsky and Bernhard Riemann

Step-by-step explanation:

Nikolai Lobachevsky (A russian mathematician born in 1792) and Bernhard Riemann (A german mathematician born in 1826) are the mathematicians that helped to discover alternatives to euclidean geometry in the nineteenth century.

7 0
4 years ago
Check my answer? Please, no joking around guys.
WITCHER [35]
This is a right angle triangle 
So we can use the tangent 
tan x = 5/20 
tan x= 0.25 
x=tan^-1 (0.25) 
x= 14.04 degrees 
So yes you're correct
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4 years ago
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Which of the following equations is written correctly for: 40 is 92% of what number
IgorLugansk [536]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Assume that the Poisson distribution applies and that the mean number of hurricanes in a certain area is 6.9 per year. a. Find t
VLD [36.1K]

Answer:

a) 9.52% probability​ that, in a​ year, there will be 4 hurricanes.

b) 4.284 years are expected to have 4 ​hurricanes.

c) The value of 4 is very close to the expected value of 4.284, so the Poisson distribution works well here.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

6.9 per year.

This means that \mu = 6.9

a. Find the probability​ that, in a​ year, there will be 4 hurricanes.

This is P(X = 4).

So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 4) = \frac{e^{-6.9}*(6.9)^{4}}{(4)!}

P(X = 4) = 0.0952

9.52% probability​ that, in a​ year, there will be 4 hurricanes.

b. In a 45​-year ​period, how many years are expected to have 4 ​hurricanes?

For each year, the probability is 0.0952.

Multiplying by 45

45*0.0952 = 4.284.

4.284 years are expected to have 4 ​hurricanes.

c. How does the result from part​ (b) compare to a recent period of 45 years in which 4 years had 4 ​hurricanes? Does the Poisson distribution work well​ here?

The value of 4 is very close to the expected value of 4.284, so the Poisson distribution works well here.

5 0
3 years ago
Divide . round your answer to the nearest tenth 8÷8766
melamori03 [73]

Answer: 0 (zero)

<em>Good Luck!</em>

<em />

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3 years ago
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