Question

Water is a polar molecule, meaning it carries partial charges (δ or δ–) on opposite sides of the molecule. for two formula units of kbr, drag two potassium ions and two bromide ions to where they would most likely appear based on the grouping of the water molecules in the area provided.

Answer 1

${{\mathbf{K}}^{\mathbf{+}}}$ will be dragged towards the side of ${\mathbf{O}}{{\mathbf{H}}^{\mathbf{-}}}$ while ${\mathbf{B}}{{\mathbf{r}}^{\mathbf{-}}}$ will be dragged towards the side of ${{\mathbf{H}}^{\mathbf{+}}}$. (Refer to the attached image)

Further explanation:

Electronegativity:

It is defined as the tendency of an atom to attract the shared electrons in the bond towards itself is known as electronegativity. The more electronegative atom will more attract the bonding electrons towards itself than the less electronegative one. Therefore the electrons will spend more time with the more electronegative atom than an electropositive atom. The electronegative atom will acquire the partial negative charge, and the electropositive atom will acquire a partial positive charge.

The polarity of the bond can be estimated by the electronegativity difference $\left({\Delta {\text{EN}}}\right)$. $\Delta{\text{EN}}$is the electronegativity difference between the two atoms that are bonded to each other. The formula to calculate $\Delta{\text{EN}}$in XY bond is as follows:

${\mathbf{\Delta EN=}}\left({{\mathbf{electronegativity of Y}}} \right){\mathbf{-}}\left({{\mathbf{electronegativity of X}}}\right)$

Here, X is the electropositive atom and Y is the electronegative atom.

Higher the electronegativity difference between the two atoms, more will be the polarity of the bond and vice-versa.

Water is a polar molecule. Hydrogen atom acquires partial positive charge while oxygen atom is partially negatively charged. So the end of the water molecule with hydrogen is positively charged, and that with oxygen is negatively charged.

In the case of a potassium-bromine bond, bromine is more electronegative than potassium. So the electrons will be more attracted towards bromine due to which it develops a partial negative charge. Potassium, being less electronegative than bromine, in turn, acquires a partial positive charge. This separation of charge results in the formation of a polar bond between potassium and bromine.

So ${{\text{K}}^+}$ will be dragged towards the side of ${\text{O}}{{\text{H}}^-}$ while ${\text{B}}{{\text{r}}^-}$ will be dragged towards the side of ${{\text{H}}^+}$.

Learn more:

1. Identification of ionic bonding: brainly.com/question/1603987

2. Which is a covalent compound? brainly.com/question/2083444

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Covalent bonding and molecular structure

Keywords: electronegativity difference, electropositive, electronegative, electrons, polar, KBr, K, Br, K+, Br-, H+, OH-, potassium, bromine, hydrogen, oxygen.

Answer 2

The side of each water molecule with the oxygen atom uncovered will be marginally negative. 
The side of each water molecule with the hydrogen atoms uncovered will be marginally positive. 
So the two Cl{-} particles will be pulled in to the biggest number of positive charges, which happen in the boxes on the upper right and lower left. 
The two Na{+} particles will be pulled in to the biggest number of negative charges, which happen in the boxes on the upper left and lower right.