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seraphim [82]
2 years ago
10

Happiness and Atoms See picture. Answer questions. Thanks

Chemistry
1 answer:
kap26 [50]2 years ago
3 0

Answer:

they are happy because their Valence shell is already fulfilled and need not to take part in further chemical equation hence they have stable electronic configuration

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2 Upper P Upper O Upper C l Subscript 3 Baseline (g) + heat double-headed arrow 2 Upper P Upper C l Subscript 3 Baseline (g) + U
gregori [183]

Answer:

The equilibrium will shift left.

Explanation:

Hope this helps <3

6 0
2 years ago
Consider an ideal gas at 30 ∘C and 1.02 atm pressure. To get some idea how close these molecules are to each other, on the avera
Nastasia [14]

Answer: They are close to each other by 41.03 m^3

Explanation:

From Ideal gas equation, PV = nRT

Where n is negligible

R is gas constant = 8.314 J/mol.k

T = 30 + 273 = 303K

P = 1.02 * 103351.5 = 103351.5 Pascal

Then;

PV = RT

V = P/RT

V = 103351.5/(8.314*303)

V = 41.03m^3

8 0
3 years ago
Read 2 more answers
An irreversible change would be?
klemol [59]

Answer:

A. Chipping ice to flakes

Explanation:

You can't reverse the ice becoming flakes. They will stay like that until they melt

8 0
2 years ago
The equilibrium constant, Kp, for the following reaction is 0.497 at 500K.PCl5(g) PCl3(g) + Cl2(g)If an equilibrium mixture of t
Anestetic [448]

<u>Answer:</u> The equilibrium partial pressure of chlorine gas is 0.360 atm

<u>Explanation:</u>

For the given chemical equation:

PCl_5(g)\rightleftharpoons PCl_3(g)+Cl2(g)

The expression of K_p for above reaction follows:

K_p=\frac{p_{Cl_2}\times p_{PCl_3}}{p_{PCl_5}}

We are given:

K_p=0.497\\p_{PCl_3}=0.651atm\\p_{PCl_5}=0.471atm

Putting values in above equation, we get:

0.497=\frac{p_{Cl_2}\times 0.651}{0.471}\\\\p_{Cl_2}=0.360atm

Hence, the equilibrium partial pressure of chlorine gas is 0.360 atm

5 0
3 years ago
Use chemical formulas to write the equation for the reaction between carbon and oxygen
yKpoI14uk [10]
C(5) + O2(g)


Hope this helped
3 0
3 years ago
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