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Komok [63]
3 years ago
7

F(x)

Mathematics
1 answer:
8_murik_8 [283]3 years ago
4 0
The answer is -4 because when you put -4,0 you will get 0 for y
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Emily has a coin with P(H) = pi and Pete has a coin with P(H) = P2. Emily tosses her coin n times, and denote the number of head
ludmilkaskok [199]

Answer:

Attached is the solution.

8 0
3 years ago
A model of space shuttle Apollo Saturn V is created width a scale of 1: 144 if the actual space shuttle has a width of 62.4 feet
ollegr [7]

The width of model is 5.2 inches

<em><u>Solution:</u></em>

Given that, model of space shuttle Apollo Saturn V is created width a scale of 1 : 144

The actual space shuttle has a width of 62.4 feet

Convert 62.4 feet to inches

1 feet = 12 inches

62.4 feet = 12 x 62.4 inches = 748.8 inches

Actual width = 748.8 inches

To find: Width of model in inches

From given,

Scale width : Actual width = 1 : 144

Let "x" be the scaled width

Then we can say,

Scale width : Actual width = 1 : 144

x : 748.8 = 1 : 144

In fractions,

\frac{x}{748.8} = \frac{1}{144}\\\\x = \frac{748.8}{144}\\\\x = 5.2

Thus the width of model is 5.2 inches

7 0
3 years ago
Solve for x and y<br><br> Pls help I will give a brainliest to who gets it right
s2008m [1.1K]

Answer:

Step-by-step explanation:

(6y-5)+(10y-41)+(12x+22)=180

16y+12x-24=180

16y+12x=204

y=12.75

x=17

3 0
3 years ago
0.5 g the f salt is equal to how many milligrams?
ruslelena [56]

Answer:

the answer would be 500 milligrams

(sorry about the answer before- I accidentally went the wrong way, but i fixed the answer)

6 0
3 years ago
(X^2+x-6)(2x^2+4x) factor completely
MissTica

Answer:

2x\left(x-2\right)\left(x+3\right)\left(x+2\right)

Step-by-step explanation:

Lets go ahead and take a step by step approach to solving your problem.

First we must start by factoring x^2+x-6.

To do this, we must break the expression into groups! Although I will also provide a definition to help you understand! For ax^2+bx+c we need to find u, v > u\cdot \:v=a\cdot \:c and u+v=b which we will group into \left(ax^2+ux\right)+\left(vx+c\right).

The values we have are...a=1,\:b=1,\:c=-6 and u\cdot v=-6,\:u+v=1.

Now we need the factors of 6 which are 1, 2, 3 and 6. We also need the negative factors which you get simply by multiplying the positives by -1 or just reversing them.

Now we need to check for every two factors if u + v = 1.

\mathrm{Check}\:u=1,\:v=-6: \:u\cdot v=-6,\:u+v=-5 \Rightarrow  \mathrm{False}

\mathrm{Check}\:u=2,\:v=-3: \:u\cdot v=-6,\:u+v=-1 \Rightarrow  \mathrm{False}

\mathrm{Check}\:u=3,\:v=-2: \:u\cdot v=-6,\:u+v=1 \Rightarrow  \mathrm{True}

\mathrm{Check}\:u=6,\:v=-1: \:u\cdot v=-6,\:u+v=5 \Rightarrow  \mathrm{False}

Therefore u=3,\:v=-2.

Now we want to \mathrm{Group\:into\:}\left(ax^2+ux\right)+\left(vx+c\right). Which is \left(x^2-2x\right)+\left(3x-6\right).

Now we must factor x from x^2-2x.

Lets apply the exponent rule of a^{b+c}=a^ba^c which means x^2=xx.

Therefore we now have xx - 2x. Lets factor out the common term of x to get x(x - 2).

Now factor 3 out of 3x-6.

Rewrite 6 as 3 * 2. 3x-3\cdot \:2.

Now factor out the common term of 3 > 3\left(x-2\right).

x\left(x-2\right)+3\left(x-2\right) > Factor out the common term of x - 2 > \left(x-2\right)\left(x+3\right).

Now lets factor 2x^2+4x.

Apply the previous exponent rule of a^{b+c}=a^ba^c > x^2=xx > 2xx+4x.

Now rewrite 4 as 2 * 2 > 2xx+2\cdot \:2x.

Now factor out the common term of 2x to get 2x(x + 2).

Combine it all and we get 2x\left(x-2\right)\left(x+3\right)\left(x+2\right).

Hope this helps!

7 0
3 years ago
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