So there are three variables, rs2 label x, rs5 label y, rs10 label z
Lets write equeations using these variables.
x+y+z=120 (A bag has a total of 120 notes)
2x+5y+10z=760 (total value)
2x+5*2y+10z=960 (twice as many rs5)

3 variables, 3 independent equations will give solution. There are a fair few ways to solve this.

8 0

2 years ago

Evaluate: 17 – 5(–3) A.–28 B. 32 C. –8 D.–21

trapecia [35]

5 times -3 = -15
17 - (-15) = 32
B.32

8 0

2 years ago

Two catalysts in a batch chemical process, are being compared for their effect on the output of the process reaction. A sample o

anzhelika [568]

Answer:

2.083 < µ1 - µ2 < 5.917

Step-by-step explanation:

We will need to construct a 90% confidence interval for the difference of 2 means where the populations are normally distributed, and their variances are equal.

The calculations of the sample means and standard deviations are done for us.

Sample 1: Catalyst 1

n = 12, x = 85, s = 4

Sample 2: Catalyst 2

n = 10, x = 81, s = 5

See attached photo for the construction of the confidence interval...

3 0

3 years ago

The length of a rectangle is one inch less than three times its width. If the perimeter of the rectangle is 118 inches, find the

IgorLugansk [536]

We can set up the width a X and, from the description the length would be 3X-1. The perimeter of a rectangle is determined by 2XL + 2Xw. Plugging into the equation 2(3X-1) + 2(X) = 118. Next distribute to get 6X-2 + 2X = 118. Combine like terms to get 8X = 120. Divide by 8 to get X = 15. The width is 15. The length is 3(15)-1 or 44. 88 +30 = 118

6 0

2 years ago