Both mean and median are measures of the center of a set of data.
Mean is normally preffered to the median except if there is an outlier that has a tendency to affect the mean.
An outlier is a data point that significantly differs from the other data points in a sample.
In the data set above, there is no outlier that will affect the mean.
Therefore, he should use the mean because there are no outliers that affect the mean.
Answer:
Step-by-step explanation:
I think the answer is C.
First start by factoring, you should get (2n-3)(n-2)=0
Then start to solve for n.
2n-3=0
n-2=0
n=2, n= 3/2
I hope that helps.
the answers are <span>the lower quartile and the maximum and The minimum and the upper quartile.</span>
Answer:
Step-by-step explanation:
4x+y=14
x-2y=8
then;
x=8-2y
substitute;
4(8-2y)+8-2y=14
32-8y+8-2y=14
40-10y=14
26=10y
y=2.6 , work out 4x+2.6=14 to get x
