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2 years ago

9

What is volume of the pyramid??

1 answer:

Bas_tet [7]2 years ago

8 0

For pyramids, the volume is defined by the product of the base area and height divided by 3. Or, V = $\frac{Bh}{3}$ Where B = area of the base and h = the height of the pyramid.

For the figure above:
B = 16 in²
h = 6 in

$V = \frac{16(6)}{3}$
V = 32

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Write the place of each underline digit.<br> 164.13<br> -

tino4ka555 [31]

Answer: 1 It's the hundreds place

Step-by-step explanation:

164.13

1 is hundreds 6 is tens 4 is one .(point) 1 is uniths and 3 is tenths

Anything after the decimal ends in (ths) (ones(uniths), tenths, hundreths) but since we only have to write

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2 years ago

HELPP!!! WILL GIVE BRAINLIEST AND 5 STARS!!!

seraphim [82]

Answer:

F=73.74 degrees

Step-by-step explanation:

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3 years ago

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jeka57 [31]

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2 years ago

Triangles ABC and DEF are similar

Sloan [31]

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2 years ago

the question is in the picture below, if you could show all your work so i can see how to do it, that would be appreciated.

ki77a [65]

m∠R = 27.03°

Solution:

Given In ΔQRP, p = 28 km, q = 17 km, r = 15 km

To find the measure of angle R:

Law of cosine formula for ΔQRP:

$r^{2}=p^{2}+q^{2}-2 pq \cos R$

Substitute the given values in the above formula.

$(15)^{2}=(28)^{2}+(17)^{2}-2 (28)(17) \cos R$

$225=784+289-952 \cos R$

$225=1073-952 \cos R$

Switch the given equation.

$1073-952 \cos R=225$

Subtract 1073 from both side of the equation.

$-952 \cos R=-848$

Divide by –952 on both sides.

$$ \cos R=\frac{106}{119}$

$$ R=\cos^{-1} \left(\frac{106}{119}\right)$

$R=27.03^\circ$

Hence m∠R = 27.03°.

7 0

3 years ago