79 is a prime, so we cannot reduce it.
Answer:
7 times.
Step-by-step explanation:
Divide 140/20.
You can use a calculator if you want.
140/20 = 7.
To check multiply 20 by 7.
20x7 = 140.
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The lnl is an absolute number which basically means it's positive regardless
So now its 7n-7=14
Simply add the 7 to the 14 to get it off the 7n side so you can simplify
Now it's 7n=21
Now just divide
21/7=3
3=N
That means 7 times N=21
Answer:
0.0918
Step-by-step explanation:
We know that the average amount of money spent on entertainment is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The mean and standard deviation of average spending of sample size 25 are
μxbar=μ=95.25
σxbar=σ/√n=27.32/√25=27.32/5=5.464.
So, the average spending of a sample of 25 randomly-selected professors is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The z-score associated with average spending $102.5
Z=[Xbar-μxbar]/σxbar
Z=[102.5-95.25]/5.464
Z=7.25/5.464
Z=1.3269=1.33
We have to find P(Xbar>102.5).
P(Xbar>102.5)=P(Z>1.33)
P(Xbar>102.5)=P(0<Z<∞)-P(0<Z<1.33)
P(Xbar>102.5)=0.5-0.4082
P(Xbar>102.5)=0.0918.
Thus, the probability that the average spending of a sample of 25 randomly-selected professors will exceed $102.5 is 0.0918.
