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Grace [21]
3 years ago
8

Plot the x-intercept of the function f(x)=(x+4) squared

Mathematics
2 answers:
expeople1 [14]3 years ago
8 0
Y = (X+4)^2
Y = (X+4)(X+4)
X intercept = y = 0
0 = (X+4)(X+4)

(X+4)=0
X = -4.
X intercept = (-4,0).
Then you would plot this X intercept on the graph of the parabola.
navik [9.2K]3 years ago
6 0

Answer:

1.Plot the x-intercept at (-4,0)

2.It is located at (-4,0)

Step-by-step explanation:

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Divide 6⁄13 by 6⁄12 . <br><br> A. 1⁄12<br> B. 9⁄16<br> C. 12⁄13<br> D. 13⁄12
nadezda [96]

6/13÷6/12=12/13 so C.

Hope this helps!

5 0
2 years ago
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Find the domain and range of the given graph?<br>HELPPPP PLSS​
Paul [167]

Answer:

The domain would be -3≤x≤2 and the range would be -5≤y≤4

Step-by-step explanation:

The domain is where the x values cover, so since on the graph the points range from having -3 as the x value to 2, x would be anything between or equal to these values.

The domain is where the y values cover, so since on the graph the points range from having -5 as the y value to 4, y would be anything between or equal to these values.

8 0
3 years ago
Which statement can be deduced from the picture?
ExtremeBDS [4]

Answer:

Angle AOD and Angle DOB are supplementary

Step-by-step explanation:

AOB is straight(180°) Line DO is a line that creates two angles

4 0
2 years ago
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A puppy and a kitten are 180 meters apart when they see each other. The puppy can run at a speed of 25 m/sec, while the kitten c
Lelechka [254]
Make two equations representing the position of each animal, p and k, for the puppy and kitten respectively.

p=25t and k=180+20t  

The puppy will catch the kitten when p=k so we can say:

25t=180+20t  subtract 20t from both sides

5t=180  divide both sides by 5

t=36

So the puppy will catch the kitten after 36 seconds.
7 0
3 years ago
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Suppose that Cecil, the tightrope walker, can only travel lengths of 5 feet, 6 feet, and 8 feet.
d1i1m1o1n [39]

Answer:

The two expressions are;

1) -8 ft. + 3 × 6 ft. = 12 feet

2) -6 ft. + 2 × 5 ft. + 8 ft. = 12 feet

Step-by-step explanation:

The given parameters are;

The lengths in feet Cecil can travel = 5 feet, 6 feet, and 8 feet

The distances Cecil can travel forward = (positive 5, 6, 8)

Backwards Cecil can travel distances of (-5, -6, -8)

Cecil can go forward past the ladder and return back

Therefore, the number expressions by which Cecil can cross a tightrope 12 feet long are;

1) -8 ft. + 3 × 6 ft. = 12 feet

Which is to go back 8 feet and then to go forward 6 feet three times

2) -6 ft. + 2 × 5 ft. + 8 ft. = 12 feet

Which is to go back 6 feet then to go forward in 5 feet two times and then in forward again in 8 feet.

7 0
3 years ago
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