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Shtirlitz [24]
3 years ago
13

The set of ordered pairs below represents a linear function. Find the rate of change. ​{(1,4​), ​(2,6​), ​(3,8​), ​(4,10​)​} The

rate of change (slope) =
Mathematics
1 answer:
Finger [1]3 years ago
6 0

Answer:

(1,2)

Step-by-step explanation:


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Step-by-step explanation:

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If 12 men are needed to run 4 machines how many men are needed to run 20 machines
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Determine whether the ordered pair (1, 1) is a solution of the inequality. y ≤ -3x+1
solong [7]

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{(1, 1) is NOT a solution of the inequality}

-------------------------------------------------------------------------------------------------------------

Given:  y \le-3x + 1

Find:  \textsf{Determine if (1, 1) is a solution of the inequality}

Solution:  In order to determine if (1, 1) is a solution we need to plug in 1 for the x values and 1 for the y values and see if the equation evaluated to true.

<u>Plug in the values</u>

  • y \le-3x + 1
  • 1 \le-3(1) + 1

<u>Simplify</u>

  • 1 \le-3 + 1
  • 1 \le-2

As we can see the expression states that 1 is less than or equal to -2 which is false therefore (1, 1) is NOT a solution of the inequality.

3 0
2 years ago
Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal
lisabon 2012 [21]

Given the following functions below,

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}

Factorising the denominators of both functions,

Factorising the denominator of f(x),

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}

Factorising the denominator of g(x),

\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}

Multiplying both functions,

undefined

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1 year ago
To find the distance around the circle?
11111nata11111 [884]

Answer:

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