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Papessa [141]
3 years ago
10

Shaun's tent (shown below) is a triangular prism. Find the surface area, including the floor, of his tent. \text{ m}^2 m 2 start

text, space, m, end text, squared

Mathematics
2 answers:
Andre45 [30]3 years ago
6 0

Answer:

52.8 square m

Step-by-step explanation:

We are given that

Length of rectangular face of Shaun's tent=5 m

Breadth of rectangular face of Shaun's tent=3 m

Base of triangular face=1.5+1.5= 3m

Height of triangular face=2.6 m

Area of rectangle=length\times breadth

Using the formula

Area of 3 rectangular face=3\times 5\times 3=45m^2

Area of two triangular face =2\times \frac{1}{2}\times base\times height

Area of two triangular face=3\times 2.6=7.8 m^2

Area of tent=Area of 3 triangular faces+area of two triangular faces

Area of tent=45+7.8=52.8m^2

erastovalidia [21]3 years ago
6 0

Answer:2400

Step-by-step explanation:

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