<h3>
Answer: 42</h3>
Explanation:
We have y = -0.9x^2 + 76x - 250 which is in the form y = ax^2+bx+c
where,
The vertex (h,k) is when the profit is maxed out.
h = -b/(2a)
h = -76/(2(-0.9))
h = 42.222 approximately
Let's plug in x values around x = 42
Try x = 41
y = -0.9x^2 + 76x - 250
y = -0.9(41)^2 + 76(41) - 250
y = 1353.10
Now try x = 42
y = -0.9x^2 + 76x - 250
y = -0.9(42)^2 + 76(42) - 250
y = 1354.4
Now try x = 43
y = -0.9x^2 + 76x - 250
y = -0.9(43)^2 + 76(43) - 250
y = 1353.9
We see that the largest profit happens when x = 42.
Average rate of change means find the slope of the secant line. So if there is a function f(x) and you want to find the average R.O.C over the interval [a,b], it would be (f(b)-f(a))/(b-a)
1. (f(3)-f(1))/(3-1)= (0-(-2))/2= 1, so D.
2. Same concept; (8-4)/(3-1)=2, so A.
3. Again, (39-(-1))/5= 8, B.
It should be a whole number.
0.80 because when you line up the decimals 0.80 is bigger
0.80
0.08
Answer:
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Step-by-step explanation:
