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Basile [38]
2 years ago
13

A rhombus can always be classified as which of the following?

Mathematics
1 answer:
ollegr [7]2 years ago
3 0

Answer:

square

rectangle

quadrilateral

Step-by-step explanation:

Sides are all equal

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a hardware store charges a $30 rental fee and $15 per day to rent a power washer which equation correctly relates to the total c
BlackZzzverrR [31]

Answer:

y = 15x + 30

Step-by-step explanation:

The $30 rental fee is a flat fee.

The $15 per day can be noted as 15x.

y = 15x + 30

6 0
3 years ago
What two positive real numbers whose product is 7272 have the smallest possible​ sum?
nadezda [96]
\sqrt{7272} and \sqrt{7272}, or as a rounded decimal 85.28 and 85.28. 

To find the smallest possible sum of roots for any product, the answer is always whatever numbers are closest together. This fact can be derived by the fact that the greatest area we can enclose with a given length is a perfect square. So we can take the square root of 7272 and use that, since they will be exactly the same number. 

If you are looking for whole numbers, you would have to go up or down until you find a factor of 7272 closest to the square root. In this case that would be 72 and 101. 
3 0
3 years ago
Find the midpoint of if A(-3, 8) andB(-7, -6).
Mama L [17]

Answer:

(-5,1)

Step-by-step explanation:

8 0
2 years ago
According to the Bohr model, the radius of a hydrogen atom is approximately 5.29 × 10-11 meters.
andrezito [222]
Simplify the expression:
41.9
7 0
3 years ago
Read 2 more answers
Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units. What would be the perimeters of the
Dmitriy789 [7]

Answer:

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

Step-by-step explanation:

Given - Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units.

To find -  What would be the perimeters of the other rectangles Orbet could make using only these 24 tiles? How do the areas of the rectangles compare?

Proof -

We know that

Are of Rectangle = Length × Breadth

And Perimeter of Rectangle = 2 (Length + Breadth )

Now,

Given that,

Orbet used 24 square tiles

And perimeter of the rectangle made = 20

So,

Possible Length of rectangle = 6

Possible breadth of Rectangle = 4

Or Vice-versa.

Total number of Rectangles possible = 4

Possibilities are -  1 × 24, 2 × 12, 3 × 8, 4 × 6

Case I :

Length of rectangle = 1

Breadth of rectangle = 24

∴ Perimeter of rectangle = 2(1 + 24) = 2(25) = 50 units

Area of rectangle = 1 × 24 = 24 unit²

Case II :

Length of rectangle = 2

Breadth of rectangle = 12

∴ Perimeter of rectangle = 2(2 + 12) = 2(14) = 28 units

Area of rectangle = 2 × 12 = 24 unit²

Case III :

Length of rectangle = 3

Breadth of rectangle = 8

∴ Perimeter of rectangle = 2(3 + 8) = 2(11) = 22 units

Area of rectangle = 3 × 8 = 24 unit²

Case IV :

Length of rectangle = 4

Breadth of rectangle = 6

∴ Perimeter of rectangle = 2(4 + 6) = 2(10) = 20 units

Area of rectangle = 4 × 6 = 24 unit²

∴ we get

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

5 0
3 years ago
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