1.) v=(l)(w)(h)
V=(9)(9)(9)
V=(81)(9)
V=729in^3
2.) (I forget if this is the real equation to this but this would give you the same answer)
V=(l)(w)(h)
————
2
V=(8)(6)(12)
————-
2
V=576/2
V=288cm^3
Answer:
x=√-1/3 y^2 +3 or x=-√-1/3 y^2 +3
Step-by-step explanation:
Let's solve for x.
3x2+y2=9
Step 1: Add -y^2 to both sides.
3x2+y2+−y2=9+−y2
3x2=−y2+9
Step 2: Divide both sides by 3.
3x^2/3= -y^2+9/3
x^2=-1/3 y^2 +3
x=√-1/3 y^2 +3 or x=-√-1/3 y^2 +3
Hope it helped!
The lowest number is 2/1 or 2.
reduce 8/4 to 4/2 which can be reduced to 2/1
Answer:
C
Step-by-step explanation:
hope it helps
The area of the square is 81 sq in, and the area of the circule is (3.14)(3 in)^2, or approx 3.14(9) sq in, or approx 28.27 sq in.
Subtract: 81 sq in - 28.27 sq in = approx. 52.73 sq in.
The difference is 52.73 sq in; the square is larger, the circle smaller.
