Ask question

Ask question

All categories

2 years ago

15

A contestant on a game show has 40 points she answers correctly and wins 20 points then she answers wrong and losses 35 points w

hat if her final score

2 answers:

JulijaS [17]2 years ago

8 0

25 is her final score. 40+20=60 60-35= 25

Brums [2.3K]2 years ago

3 0

She would have 25 points because 40+20 is 60, and 60-35=25.

You might be interested in

Y = 5+5(x-8)<br> Can someone please solve this?

vekshin1

y = 5+5(x-8)

y = 5 + 5x - 40

y = 5x - 35

7 0

3 years ago

Simplify the expressions<br> (a^2b^-3/a^-2b^2)^2

poizon [28]

Answer:

$(\frac{a^{2}b^{-3} }{a^{-2}b^{2} })^{2} = (a^{2-(-2) }b^{-3 - 2})^{2} \\ = (a^{4}b^{-5} )^{2} = (a^{4})^{2} (b^{-5})^{2} = a^{8} b^{-10}$

Here is for you.

Step-by-step explanation:

6 0

2 years ago

A contractor has installed a silt fence around an area that is semi-circular and level to prevent soil from the construction sit

monitta

We know is a semi-circle, so let us use the equation for the area of a circle instead, and then, half it
so, the diameter is 1100, meaning the radius is half that, or 550

so... $\textit{area of a circle}=\pi r^2\qquad r=radius=\frac{diameter}{2}=\frac{1100}{2}=550
\\ \quad \\
\textit{area of a semi-circle}=\cfrac{\pi r^2}{2}\impliedby \textit{enclosed acres}
\\ \quad \\
\textit{circumference of a circle}=2\pi r
\\ \quad \\
\textit{circumference of a semi-circle}=\cfrac{2\pi r}{2}\impliedby \textit{linear feet of fence}$

6 0

2 years ago

Find a power series for the function, centered at c. g(x) = 4x x2 2x − 3 , c = 0

BartSMP [9]

The power series for given function $g(x)=\frac{4x}{(x-1)(x+3)}$ is $g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)$

For given question,

We have been given a function g(x) = 4x / (x² + 2x - 3)

We need to find a power series for the function, centered at c, for c = 0.

First we factorize the denominator of function g(x), we have:

$\Rightarrow g(x)=\frac{4x}{(x-1)(x+3)}$

We can write g(x) as,

$\Rightarrow g(x)=\frac{1}{x-1}+\frac{3}{x+3}\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1+\frac{x}{3} }\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1-(-\frac{x}{3} )}\\$

We know that, $\frac{1}{1-x}=\sum{_{n=0}^\infty}~{x^n}$ if |x| < 1

and $\frac{1}{1-(-\frac{x}{3} )}=\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n$ if $|\frac{x}{6}| < 1$

$\Rightarrow g(x)=-\sum{_{n=0}^\infty}~x^n+\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n\\$ if |x| < 1 and if $|\frac{x}{6}| < 1$

$\Rightarrow g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)$ if |x| < 1

Therefore, the power series for given function $g(x)=\frac{4x}{(x-1)(x+3)}$ is $g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)$

Learn more about the power series here:

brainly.com/question/11606956

#SPJ4

5 0

1 year ago

F(x) = {5x - 1, if x < 2 Find f(-4)<br> x-9, if x ≥ -2

Jobisdone [24]

Since -4 is less than 2, use the first equation
5(-4) - 1 = -20 - 1 = -21

3 0

2 years ago