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kifflom [539]
3 years ago
13

An engineering scale model shows a church that is 2 inches tall. if the scale is 1 inch = 256 feet, how tall is the actual churc

h
Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0

Answer:

Actual height of church = 512 feet

Step-by-step explanation:

Given:

Scale model;

1 inch = 256 feet

Height of church (Scale model) = 2 inches

Find:

Actual height of church

Computation:

Actual height of church = Height of church (Scale model) x scale length

Actual height of church = 2 inches x 256 feet/inches

Actual height of church = 2 x 256 feet

Actual height of church = 512 feet

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drek231 [11]

Answer:

7/8 - 1/2

= 0.37

hope it helps!

5 0
3 years ago
I’m trying to help my brother with his homework but I’m confused can someone help? Btw the last one is (D.140)
My name is Ann [436]

The dog must take 125 steps if Evan takes 50.

Option C is correct

<h3>What exactly is a series query?</h3>

These problems are based on numerical series that adhere to a logical rule or pattern derived from fundamental notions in mathematics. The pattern must be examined from a certain sequence that is presented. The following question asks you to anticipate the subsequent number in the series using the same formula.

<h3>Sequence and series types?</h3>

arithmetic progressions Sequences in geometry. Harmonic patterns.

Evan takes ten steps before the dog takes 25 steps.

Evan takes 28 steps first, then the dog takes 70 steps.

Evan takes 50 steps, followed by the dog's 125 steps.

To know more about series question visit:-

brainly.com/question/16415816

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3 0
1 year ago
In this exercise, we estimate the rate at which the total personal income is rising in a metropolitan area. In 1999, the populat
DiKsa [7]

Answer:

the rate at which total personal income was rising in the area in 1999 is $1,580,507,200 billion

Step-by-step explanation:

From the given information:

Let consider y to represent the number of years after 1999

Then the population in time (y) can be expressed as:

P(y) = 9400y + 924900

The average annual income can be written as:

A(y) = 1400y + 30388

The total personal income = P(y)  ×  A(y)

The rate at which the total personal income is rising is T'(y) :

T'(y) = P'(y)  ×  A(y)  + P(y)  ×  A'(y)

T'(y) = (9400y + 924900)' (1400y + 30388) + (9400y + 924900) (1400y + 30388)'

T'(y) = 9400(1400y + 30388) + (9400y + 924900) 1400

Since in 1999 y =0

Then:

T'(0) = 9400(1400(0) + 30388) + (9400(0) + 924900) 1400

T'(0) = 9400(30388) + (924900)1400

T'(0) = $1,580,507,200 billion

Therefore; the rate at which total personal income was rising in the area in 1999 is $1,580,507,200 billion

8 0
3 years ago
Is this an error? Confused! HELP!!!
MArishka [77]
Put 10.5% to the left of 0.11, because 10.5% is 0.105
between 0.09 and 0.11, you have 0.090, 0.095, 0.100, 0.105, 0.110
3 0
3 years ago
Read 2 more answers
Please help Will give brainliest!!
murzikaleks [220]

Answer:

1/6  (16.667%)

Step-by-step explanation:

8 0
2 years ago
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