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kifflom [539]
2 years ago
13

An engineering scale model shows a church that is 2 inches tall. if the scale is 1 inch = 256 feet, how tall is the actual churc

h
Mathematics
1 answer:
SVETLANKA909090 [29]2 years ago
8 0

Answer:

Actual height of church = 512 feet

Step-by-step explanation:

Given:

Scale model;

1 inch = 256 feet

Height of church (Scale model) = 2 inches

Find:

Actual height of church

Computation:

Actual height of church = Height of church (Scale model) x scale length

Actual height of church = 2 inches x 256 feet/inches

Actual height of church = 2 x 256 feet

Actual height of church = 512 feet

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Common factors of 35 and 60
OLga [1]
Factors of 35: 1; 5; 7; 35
Factors of 60: 1; 2; 3; 4; 5; 6; 10; 12; 15; 20; 30; 60

<span>Greatest Common Factor GCF(35; 60) = 5</span>

4 0
3 years ago
Which set of values could be the side lengths of a 30-60-90 triangle?
jeyben [28]
If we say that side "a" is the shortest (adjacent), side "b" is the second shortest (opposite), and side "c" is the longest (hypotenuse): then angle A would be 30°,  angle B would be 60°, and angle C would be 90°

tan B = b/a
 or
a tan B = b

they have 4 as the smallest value in all four options, so we know that a=4

4 tan 60° = b
tan 60° = √3
so, 4 tan 60° = 4√3
b=4√3

that leaves two options left, so now we find "c":

c^2 = (a^2) + (b^2)
OR
c= \sqrt{a^{2} + b^{2}}

c= \sqrt{4^{2}+(4\sqrt{3})^{2}}

c= \sqrt{16+48} \\ c=\sqrt{64} \\ c=8

so a=4, b=4√3, and c=8

Making your answer B
3 0
3 years ago
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The falcons basketball team beat the tigers by 7 points in a game. The total points scored by both teams was 83. Write and solve
Blizzard [7]
Falcons = 45
Tigers = 38

83-7=76
76/2=38 (Tigers)
38+7=45 ( Falcons)
6 0
3 years ago
18.746+3.079 what is the reason<br>​
Sav [38]

Answer:

21.825

Step-by-step explanation:

1   1 1

18.746

3.079

+____

  21.825     hope this helps :)

3 0
3 years ago
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maksim [4K]

Answer:

y

Step-by-step explanation:

that easy just isolate the variables

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1 year ago
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