Answer:
0
I hope this is the correct answer
The standard form of a quadratic equation is ,
ax² + bx + c = 0.
And the formula to find the discriminant is b² - 4ac.
Here the first step is to change the given equation into standard form. So, add 1 to each sides of the equation. Therefore,
2x² – 9x + 2+1 = –1 + 1
2x² – 9x + 3 = 0
Next step is to compare the given equation with this equation to get the value of a, b and c.
After comparing the equations we will get a = 2, b = -9 and c = 3.
So, discriminant = b²- 4ac
=( -9)²-4 (2)(3)
= 81 - 24
= 57
So, discriminant of the given equation is 57.
57 is greater than 0 and square root of 57 will result real number.
So, the correct choice is C: The discriminant is greater than 0, so there are two real roots.
The answer for the given above is letter "a, -6r2s4t3". This is obtained by dividing 18 by -3 and subtracting the exponent below with that from above of the same variable. For r, subtract 2 from 4 to get 2. For s, subtract 1 from 5 to get 4 and lastly for t, subtract 3 from 6 to get 3.
Answer:
LCM = 20, GCF = 9
Step-by-step explanation:
