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2 years ago

According to the graph, what is the experimental probability of selecting the letter T?

Mathematics

1 answer:

valentina_108 [34]2 years ago

4 0

Answer: the answer is 1/5 I put 4 and got it wrong, after submitting the test it showed me the answer

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The factors of p2-2pq+q are

s2008m [1.1K]

Answer:

Unsure

Step-by-step explanation:

did you forget the q^2

if so,

(p-q)^2

if not,

you can't simplify any further

5 0

2 years ago

Read 2 more answers

Please help me? :\ :/

4vir4ik [10]

No it can’t because a square is not a circle and their is no way for it to become a circle

4 0

2 years ago

Yoko is buying a car from a local car dealership. She wants to get the lowest interest rate possible. Which will most likely hel

Nuetrik [128]

Answer:

B)making sure she has a positive credit history

Step-by-step explanation:

Yoko is buying a car from a local car dealership. She wants to get the lowest interest rate possible.

B) making sure she has a positive credit history - will most likely help her get the lowest interest rate.

Getting low interest rates does not depend on the way you talk or if you have a driver licence.

It depends on your previous credit history and credit scores. When you have good scores, this means you have always paid your debts on time and this makes sure that you will do the same in future.

So, you get low interest rates based on good credit history.

8 0

2 years ago

Read 2 more answers

I need help with this one math question please!

den301095 [7]

Answer:

see explanation

Step-by-step explanation:

Assuming the fractions are being multiplied

Factorise the denominators of both fractions

x² - 3x - 10 = (x - 5)(x + 2)

x² + x - 12 = (x + 4)(x - 3)

The product can now be expressed as

$\frac{x-5}{(x-5)(x+2)}$ × $\frac{x+2}{(x+4)(x-3)}$

Cancel (x - 5) and (x + 2) on the numerators/ denominators, leaving

$\frac{1}{(x+4)(x-3)}$ = $\frac{1}{x^2+x-12}$

3 0

2 years ago

The first two terms in an arithmetic progression are -2 and 5. The last term in the progression is the only number in the progre

Rudik [331]

Given:

The first two terms in an arithmetic progression are -2 and 5.

The last term in the progression is the only number in the progression that is greater than 200.

To find:

The sum of all the terms in the progression.

Solution:

We have,

First term : $a=-2$

Common difference : $d = 5 - (-2)$

$= 5 + 2$

$= 7$

nth term of an A.P. is

$a_n=a+(n-1)d$

where, a is first term and d is common difference.

$a_n=-2+(n-1)(7)$

According to the equation, $a_n>200$ .

$-2+(n-1)(7)>200$

$(n-1)(7)>200+2$

$(n-1)(7)>202$

Divide both sides by 7.

$(n-1)>28.857$

Add 1 on both sides.

$n>29.857$

So, least possible integer value is 30. It means, A.P. has 30 term.

Sum of n terms of an A.P. is

$S_n=\dfrac{n}{2}[2a+(n-1)d]$

Substituting n=30, a=-2 and d=7, we get

$S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]$

$S_{30}=15[-4+(29)7]$

$S_{30}=15[-4+203]$

$S_{30}=15(199)$

$S_{30}=2985$

Therefore, the sum of all the terms in the progression is 2985.

6 0

2 years ago