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vfiekz [6]
3 years ago
12

Match each of the following complex numbers with its equivalent expression.

Mathematics
1 answer:
Yanka [14]3 years ago
6 0

Answer:

Therefore

i^{110}=-1

i^{92}=1

i^{245}=i

i^{347}=-i

Step-by-step explanation:

Complex Number :

A complex number is a number that can be expressed in the form

a + bi

where a and b are real numbers, and

' i ' is called an imaginary number.

The value of i is given as

i=\sqrt{-1}

Squaring both the side we get

i^{2}=(\sqrt{-1})^{2}\\\therefore i^{2}=-1

Therefore on substituting we get

For i^110

i^{110}=(i^{2})^{55}=(-1)^{55}=-1

Similarly for i^92

i^{92}=(i^{2})^{46}=(-1)^{46}=1

Similarly for i^245

i^{245}=(i^{2})^{122}\times i=(-1)^{122}\times i=1\times i =i

Similarly for i^347

i^{347}=(i^{2})^{173}\times i=(-1)^{173}\times i=-1\times i =-i

Therefore

i^{110}=-1

i^{92}=1

i^{245}=i

i^{347}=-i

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Let consecutive odd numbers be  

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According to condition (x) +(x+2) -27 = 3(x+4)

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