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kicyunya [14]
3 years ago
5

Joyce says that the figure below made I cm cubes has a volume of 5 cubic centimeters explain her mistakes

Mathematics
1 answer:
Trava [24]3 years ago
6 0

Answer:

see the explanation

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The volume of a cube is equal to

V=b^3

where

b is the length side of the cube

In this problem we ha a cubes with a length side equal to 1 cm

so

b=1\ cm

substitute

V=(1)^3=1\ cm^3

The volume of each cube is equal to one cubic centimeter

so

To find out the volume of the figure, multiply the number of cubes by 1 cm^3

Looking at the figure

The total number of cubes is 6

therefore

The total volume is

6(1)=6\ cm^3

Joyce's mistake was counting 5 cubes instead of 6 (there is one cube that is not in sight)

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The answer is Graph X.

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Please Mark Brainliest If This Helped!

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3 years ago
Medicare would like to test the hypothesis that the average monthly rate for one-bedroom assisted-living facility is equal to $3
aliina [53]

Answer:

C) more than the absolute value of the critical value, we can conclude that the average monthly rate for an assisted-living facility is not equal to $3,300.

Step-by-step explanation:

Hello!

Interest hypothesizes is " the average monthly rate for one-bedroom assisted-living facility is equal to $3300" symbolically: μ = 3300

The study variable is:

X: Monthly rate for a one-bedroom assisted-living facility.

Since there is no information about the distribution of the variable, to be able to study the population mean, I'll assume that the variable has a normal distribution.

The hypothesis is:

H₀: μ = 3300

H₁: μ ≠ 3300

α: 0.05

The statistic to use, considering that there is no known population information and the sample size, is a Student t:

t= <u> X[bar] - μ </u> ~t_{n-1}

       S/√n

n= 12

X[bar]= $3690

S= $530

Using the sample data, calculate the statistic value:

t= <u> 3690 - 3300 </u> = 2.549

       530/√12

The rejection region for this test is two-tailed, with critical values:

t_{n-1; \alpha /2} = t_{11; 0.025} = -2.201

t_{n-1;1-\alpha /2} = t_{11; 0.975} = 2.201

The decision rule is:

Reject the null hypothesis if t ≤ -2.201 or if t ≥ 2.201

Not reject the null hypothesis if -2.201 < t < 2.201

Since the calculated value (2.549) is greater than the right critical value (2.201) the decision is to reject the null hypothesis.

With a signification level of 5%, there is enough evidence to reject the null hypothesis. This means that the population mean of the monthly rate for a one-bedroom assisted living facility is different from $3300.

I hope it helps!

7 0
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Answer:

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