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IRINA_888 [86]
3 years ago
13

Which transformation is a rigid transformation?

Mathematics
2 answers:
kiruha [24]3 years ago
8 0

Answer:

Reflections, translations, rotations, and combinations of these three transformations are "rigid transformations".

Step-by-step explanation:

Stolb23 [73]3 years ago
7 0

Answer:

isometry

Step-by-step explanation:

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A ball is tossed between three friends. The first toss is 8.6 feet, the second is 5.8 feet, and the third toss is 7.5 feet, whic
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angles formed by these tosses are  79.45, 59.02 and 41.53 degrees to the nearest hundredth.

<u>Step-by-step explanation:</u>

Here , We have a triangle with sides of length 8.6 feet, 5.8 feet and 7.5 feet.

The Law of Cosines (also called the Cosine Rule) says:

c^2 = a^2 + b^2 - 2ab (cosx)

Using the Cosine Rule to find the measure of the angle opposite the side of length 8.6 feet:

⇒ c^2 = a^2 + b^2 - 2ab (cosx)

⇒ c^2 -a^2 - b^2 = -2ab (cosx)

⇒ (cosx) =\frac{ c^2 -a^2 - b^2}{ -2ab}

⇒ (cosx) =\frac{(8.6^2 - 5.8^2 - 7.5^2)}{ ( -2(5.8)7.5)}

⇒ (cosx) =0.18310

⇒ cos^{-1}(cosx) = cos^{-1}(0.18310)

⇒ x = 79.45

The Law of Sines (or Sine Rule) is very useful for solving triangles:

\frac{a}{sin A} = \frac{ b}{sin B} =  \frac{c}{sin C}

We can now find another angle using the sine rule:

⇒\frac{ 8.6 }{ sin 79.45} = \frac{7.5}{ sin Y}

⇒sin Y = \frac{(7.5 (sin 79.45))}{  8.6}

⇒Y = 59.02 degrees

So, the third angle =180 - 79.45 - 59.02 = 41.53 degrees.

Therefore, angles formed by these tosses are  79.45, 59.02 and 41.53 degrees to the nearest hundredth.

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4 years ago
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Your answer should be organize, correct me if I’m wrong !
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Please help! If the m = 1/2 and the b = -2, then the linear equation is:
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Answer:

y=1/2x-2

you write it in y=mx+b form

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Pleeeeese help me as fast as you can!!!
Aleonysh [2.5K]

Answer:

A. y=3x-10

C. y+6=3(x-15)

Step-by-step explanation:

Given:

The given line is 6x+18y=5

Express this in slope-intercept form y=mx+b, where m is the slope and b is the y-intercept.

6x+18y=5\\18y=-6x+5\\y=-\frac{6}{18}x+\frac{5}{18}\\y=-\frac{1}{3}x+\frac{5}{18}

Therefore, the slope of the line is m=-\frac{1}{3}.

Now, for perpendicular lines, the product of their slopes is equal to -1.

Let us find the slopes of each lines.

Option A:

y=3x-10

On comparing with the slope-intercept form, we get slope as  m_{A}=3.

Now, m\times m_{A}=-\frac{1}{3}\times 3=-1. So, option A is perpendicular to the given line.

Option B:

For lines of the form x=a, where, a is a constant, the slope is undefined. So, option B is incorrect.

Option C:

On comparing with the slope-point form, we get slope as  m_{C}=3.

Now, m\times m_{C}=-\frac{1}{3}\times 3=-1. So, option C is perpendicular to the given line.

Option D:

3x+9y=8\\9y=-3x+8\\y=-\frac{3}{9}x+\frac{8}{9}\\y=-\frac{1}{3}x+\frac{8}{9}

On comparing with the slope-intercept form, we get slope as  m_{D}=-\frac{1}{3}.

Now, m\times m_{D}=-\frac{1}{3}\times -\frac{1}{3}=\frac{1}{9}. So, option D is not perpendicular to the given line.

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