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3 years ago

Simplify (4^2)^5 ^ = exponent please help will award the Brainlyest

Mathematics

1 answer:

Marrrta [24]3 years ago

3 0

Answer:

Step-by-step explanation:

Here you go mate'

step 1

(4^2)^5 equation

step 2

(4^2)^5 multiply the equation 5 times

(4^2)(4^2)(4^2)(4^2)(4^2)

step 3

(4^2)(4^2)(4^2)(4^2)(4^2) solve

4^10

answer

4^10=1048576

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Please help asap! I need this done tomorrow

d1i1m1o1n [39]

Answer:

2x + 3y = 4

Step-by-step explanation:

The standard form:

Ax + By = C

So from the given form, arrange it to the standard form.

First, simplify the form by distribution.

y + 6 = -2/3(x - 11)

y + 6 = -2/3x + 22/3

Next, you make the fractions into whole by multiplying both sides by 3(this would eliminate all fractions).

(3)y + 3(6) = 3(-2/3x) + 3(22/3)

3y + 18 = -2x + 22

Now, arrange the "Ax" and the "C's".

3y + 18 = -2x + 22

2x + 3y + 18 = 22

2x + 3y = 22 - 18

2x + 3y = 4

Cheers!

6 0

3 years ago

Your $440 gets 5.8% compounded annually for 8 years. What will your $440.00 be worth in 8 years?

MArishka [77]

Answer:

400.00

Step-by-step explanation:

5 0

3 years ago

Find the coordinates of the missing endpoint if B is the midpoint of AC. C(-5,4), B(-2,5) I need the steps and answer pls and ty

mylen [45]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ x}}\quad ,&{{ y}})\quad 
% (c,d)
C&({{ -5}}\quad ,&{{ 4}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)$

$\bf \left( \cfrac{-5+x}{2}~,~\cfrac{4+y}{2} \right)=\stackrel{B}{(-2,5)}\implies 
\begin{cases}
\cfrac{-5+x}{2}=-2\\\\
-5+x=-4\\
\boxed{x=1}\\
----------\\
\cfrac{4+y}{2}=5\\\\
4+y=10\\
\boxed{y=6}
\end{cases}$

3 0

3 years ago

Terry practices the same amount of time each day for his soccer tryouts. In 4 days, he has practiced for 360 minutes. Let x repr

n200080 [17]

Answer:

Step-by-step explanation:

390 ( 40; 6 )

7 0

2 years ago

A family has two cars. The first car has a fuel efficiency of 15 miles per gallon of gas and the second has a fuel efficiency of

professor190 [17]

The fuel consumption of each of the cars during the week are as follows;

The first car consumes 20 gallons of fuel.

The second car consumes 30 gallons of fuel.

Reasons:

Fuel efficiency of the first car = 15 miles per gallon

Fuel efficiency of the second car = 35 miles per gallon

Combined distance traveled by the two cars in a week = 1,350 miles

The total gas consumption during the week = 50 gallons

Let x represent the number of gallons consumed by the first car, and let y

represent the number of gallons consumed by the second car, we get the

following system of simultaneous equations;

15·x + 35·y = 1,350...(1)

x + y = 50...(2)

Therefore;

y = 50 - x

Which gives;

15·x + 35 × (50 - x) = 1,350

15·x + 1,750 - 35·x = 1,350

1,750 - 1,350 = 35·x - 15·x = 20·x

400 = 20·x

x = 400 ÷ 20 = 20

The number of gallons consumed by the first car, x = 20 gallons

From equation (2), we have;

x + y = 50

y = 50 - x

Therefore;

y = 50 - 20 = 30

The number of gallons consumed by the second car, y = 30 gallons

Learn more about word problems that lead to simultaneous equations here:

brainly.com/question/1717365

6 0

2 years ago