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3 years ago

We’re five and twenty two hundredths centimeters as a decimal

Mathematics

2 answers:

nika2105 [10]3 years ago

7 0

5.22 is 5 22/100 as a decimal

GREYUIT [131]3 years ago

4 0

You answer will be 5 22/100

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Ben, Shaneeka, and Phil live on the same street. Ben lives 6/11 mile north of Phil, and 1/3 mile north of Shaneeka. How far does

Norma-Jean [14]

Answer:

Shaneeka live from Phil 7/33 mile far.

Step-by-step explanation:

Given:

Ben lives 6/11 mile north of Phil, and 1/3 mile north of Shaneeka.

Now, to get how far does Shaneeka live from Phil.

So, by subtracting the distance from 6/11 mile north where Ben lives from Phil to 1/3 mile north where Ben lives from Shaneeka:

$\frac{6}{11} -\frac{1}{3}$

$=\frac{6\times 3 -1\times 11}{33}$

$=\frac{18-11}{33}$

$=\frac{7}{33}$

Therefore, Shaneeka live from Phil 7/33 mile far.

7 0

3 years ago

Difference of 86.42 - 2.1.

densk [106]

Answer:

The first one

Step-by-step explanation:

The decimals line up when you subtract them

3 0

3 years ago

Read 2 more answers

Please help. Answer only if you know the correct answer. I’ll mark you as brainliest if correct.

Allisa [31]

Answer:

37.2 mph

Step-by-step explanation:

They are going 0.60 times the speed that converts to 62 mph. Their speed is approximately ...

0.60 × 62 mph = 37.2 mph

4 0

3 years ago

A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate

Lyrx [107]

Answer:

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

$\frac{dV}{dt}=4 \ m^3/s$

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is $V=\pi r^2 h$

$=( \pi \times 2^2\times h)\ m^3$

$\therefore V= 4\pi h$

Differentiating with respect to t.

$\frac{dV}{dt}=4\pi \frac{dh}{dt}$

Putting the value $\frac{dV}{dt}$

$\Rightarrow 4\pi \frac{dh}{dt}=4$

$\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}$

$\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}$

The rate change of height does not depend on the height.

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

3 0

3 years ago

rosa works north of her home. her husband works east they leave at the sane time. by the time rosa is 7 miles from home, the dis

Gennadij [26K]

This problem requires the Pythagorean therom.

The distance between them is 7.

Since the distance between them is one more mile than ray's distance from home ray is 6 miles from home.

So rosa is $\sqrt{7^2-6^2}$

So rosa is $\sqrt{13}$ miles away from home.

Rosa is about 3.6 miles from home.

7 0

3 years ago