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3 years ago

NO LINKS Help please!Need the value of both h and k

Mathematics

1 answer:

ANEK [815]3 years ago

5 0

I have the same question that i don’t understand sorry i’m commenting so i can see if anyone else gets that answer

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Solve for x: |2x + 12| =

igor_vitrenko [27]

Dddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd

6 0

2 years ago

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10 points!!!!! Do 14 and 15 only hurry please.

Aleksandr [31]

Answer:

8. x = 16

9. x = 10

14.

m ∠RSU = 130°

m ∠UST = 50°

15.

m ∠RSU = 124°

m ∠UST = 56°

Step-by-step explanation:

Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF

That is , (x + 15)° = 31°

x = 31 - 15 = 16

Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF

That is ,

(6x - 4)° = 56°

6x = 56 + 4

6x = 60

x = 10

14.

13x + 5x = 180° [straight line angles ]

18x = 180

x = 10

m ∠RSU = 130°

m ∠UST = 50°

15.

4x + 12 + 2x = 180° [ straight line angles]

6x = 180 - 12

6x = 168

x = 28

m ∠RSU = 4(28) + 12 = 112 + 12 = 124°

m ∠UST = 2(28) = 56°

3 0

3 years ago

Read 2 more answers

PLEASE HELP TRYING TO MAKE HONOR ROLL

FromTheMoon [43]

Answer:

it is B. -11 and 47

Step-by-step explanation:

you have to take away 47 and 11 and it equals 36.

3 0

3 years ago

Which table represents the graph of a logarithmic function in the form y=log3x when b>1?

alex41 [277]

Answer:

The satisfied table of the given function $y = log_{b} (x)$

x 1/8 1/4 1/2 1 2

y -3 -2 -1 0 1

Step-by-step explanation:

Explanation :-

Given logarithmic function $y = log_{b} (x)$ if b >1

Given first table

put x = $\frac{1}{8}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{8} )$

$y = log_{2} (2^{-3} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-3} ) = -3 log_{2} (2) = -3 (1) = -3$

y = -3

ii)

put x = $\frac{1}{4}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{4} )$

$y = log_{2} (2^{-2} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-2} ) = -2 log_{2} (2) = -2 (1) = -2$

y = -2

iii)

put x = $\frac{1}{2}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{2} )$

$y = log_{2} (2^{-1} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-1} ) = -1 log_{2} (2) = - (1) = -1$

y = -1

iv)

put x = 1 given b > 1 so we can choose b = 2

$y = log_{2} (1 )$ = 0

y = 0

v)

put x = $2$ given b > 1 so we can choose b = 2

$y = log_{2} (2 )$

y = 1

Final answer:-

The satisfied table of the given function

x 1/8 1/4 1/2 1 2

y -3 -2 -1 0 1

8 0

3 years ago

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A certain experimental mathematics program was tried out in 2 classes in each of 32 elementary schools and involved 37 teachers.

zheka24 [161]

Answer:

A) 0 and 13

Step-by-step explanation:

64 - 37 = 27

27/2 = 13.5

13 teachers can teach 3 classes at max

6 0

3 years ago

**NO LINKS** Help please!Need the value of both h and k

NO LINKS Help please!Need the value of both h and k