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yKpoI14uk [10]
3 years ago
7

Hey I am struggling with this question and was hoping someone could help me before 7:00PM CST.

Mathematics
2 answers:
mariarad [96]3 years ago
4 0

\bf \cfrac{5x}{x^2+2x}\div \cfrac{30x^2}{x+2}\implies \cfrac{5x}{x^2+2x}\cdot \cfrac{x+2}{30x^2}\implies \cfrac{\begin{matrix} 5x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}{x~~\begin{matrix} (x+2) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}\cdot \cfrac{\begin{matrix} x+2\\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} }{\begin{matrix} 5x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}\cdot 6x} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \cfrac{1}{6x^2}~\hfill

yKpoI14uk [10]3 years ago
3 0

Answer: x^3+30x+75

             -----------------------------

                       15x

Step-by-step explanation:

5x/x^2+2x÷30x^2/x+2

1/15x^5+2x^3+5x^2

---------------------------

x^3

x^3+30x+75

-----------------------------

15x

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Step-by-step explanation:

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9514 1404 393

Answer:

  a) ∆ABC ~ ∆EDC by AA similarity

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Step-by-step explanation:

a) Two angles in each triangle are the same, so the AA similarity postulate can be used to declare the ∆ABC ~ ∆EDC. (Each triangle includes a right angle and angle C.)

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