Answer:
The minimum value of a function is the lowest point of a vertex. If your quadratic equation has a positive a term, it will also have a minimum value. ... If you have the equation in the form of y = ax^2 + bx + c, then you can find the minimum value using the equation min = c - b^2/4a.
Basically you substitute 16 in for x.
f(16) = 3/4(16) - 5
f(16) = 12 - 5
f(16) = 7
<span>10!/(10-6)!
=
3628800/24
=
151200
</span> So the answer is 151200
Answer:
1/12
Step-by-step explanation:
Hope this helps!
Answer:
y = (x - 
)² - 
Step-by-step explanation:
Given
y = (x + 2)(x - 3) ← expand factors
= x² - x - 6
Use the method of completing the square
add/ subtract ( half the coefficient of the x- term )² to x² - x
y = x² + 2(- ) x + 
- - 6
= (x - )² -
