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2 years ago

Ok guys i have only 1 hr to get this. Determine the y-intercept for the equation 3x + 2y = 12. HELP

Mathematics

1 answer:

sukhopar [10]2 years ago

5 0

Answer:

x= -2/3 y+4

Step-by-step explanation:

Let's solve for x.

3x+2y=12

Step 1: Add -2y to both sides.

3x+2y+−2y=12+−2y

3x=−2y+12

Step 2: Divide both sides by 3.

−2y+12

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I need help on this problem (4x+8)+(7x+3)

SpyIntel [72]

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ You have to collect like terms

In other words, add together the values that have x in them and add together the values that don't

4x + 7x = 11x

8 + 3 = 11

The answer is 11x + 11

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

4 0

3 years ago

Read 2 more answers

The mean is <br> A: Sometimes<br> B: always<br> C: never

podryga [215]

I guess the mean is always

this question is not clear.

6 0

2 years ago

Which is an equation in slope intercept form of the line that contains the points (7,-9) and (8,-7)

jeyben [28]

Answer:

y=2x-23

Step-by-step explanation:

m=(-9+7)/(7-8)=-2/-1=2

y=2x+b

-7=2(8)+b

-7-16=b

b=-23

y=2x-23

7 0

3 years ago

Question: A square with sides of length 5 is positioned inside a square with sides of length 7. What is the total area between t

Sergio [31]

Answer:

The total area between the squares is of 24 units squared.

Step-by-step explanation:

Area of a square:

The area of a square of side length l is given by:

$A = l^2$

Area between figures:

The area between two figures is the area of the larger figure subtracted by the area of the smaller figure.

Larger square:

Square with side of length 7. So

$A_l = 7^2 = 49$

Smaller square:

Square with side of length 5. So

$A_s = 5^2 = 25$

What is the total area between the squares? 

$T = A_l - A_s = 49 - 25 = 24$

The total area between the squares is of 24 units squared.

6 0

2 years ago

Please help me !!!!!!

cestrela7 [59]

Given:

The set of pair and graphs.

To find:

The domain and range.

Solution:

We know that,

Domain is the set of x-values or input values.

Range is the set of y-values or output values.

(a)

The given set of ordered pairs is

{(-3,3),(5,5),(-3,2),(5,3)}

Here, the x-coordinates are -3, 5, -3, 5.

A set contains distinct values.

Therefore, the domain is {-3,5}.

(b)

The graph is given.

From the given graph the set of ordered pairs is

{(-2,1),(-1,0.5),(-1,3),(0,0),(0,2),(1,0.5),(1,3)(2,1)}

Here, the y-values are 1, 0.5, 3, 0, 2, 0.5, 3, 1.

Therefore, the range is {0, 0.5, 1, 2, 3}.

(c)

The graph is given.

From the given graph the set of ordered pairs is

{(-2,3),(-1,3),(0,1),(2,4)}

Here, the x-values are -2, -1,0, 2.

Therefore, the domain is {-2,-1,0,2}.

4 0

3 years ago