Answer:
above is the answer to the question, second picture for clear view
You're looking for a value

such that

Because the distribution is symmetric, the value of

in either case will be the same.
Now, because the distribution is continuous, you have that

The mean for the standard normal distribution is

, and because the distribution is symmetric about its mean, it follows that

.

You can consult a

score table to find the corresponding score for this probability. It turns out to be

.
Step-by-step explanation:

The answer is 25 degrees.
This is how you solve the equation, first you must know that the straight like ABC=180, DBC is 130, so the remaining amount is 50 degrees, BE is a bisector of ABD which means it splits ABD right down the middle. So ABE+EBD=50 degrees, 25+25=50 since both sides MUST be equal in order for BE to be a bisector of ABD.
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The slope of that line is -1, so m = -1.
The point you were told to use is (-2,2), so point-slope form starts as:
( y - 2 ) = -1 • ( x - (-2) )
But we'd clean up that x-(-2) to be x+2.
y - 2 = -1 ( x+2 )