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IceJOKER [234]
3 years ago
15

ABC Corp. has outstanding accounts receivable totaling $6.5 million as of December 31 and sales on credit during the year of $24

million. There is also a credit balance of $12,000 in the allowance for doubtful accounts. If the company estimates that 6% of its outstanding receivables will be uncollectible, what will be the amount of bad debt expense recognized for the year
Mathematics
1 answer:
Elden [556K]3 years ago
3 0

Answer:

$378,000

Step-by-step explanation:

The computation of the bad debt expense for the year is shown below:

Bad debt expense = Outstanding account receivable × estimated percentage given - credit balance of allowance for doubtful account

= $6,500,000 × 0.06 - $12,000

= $390,000 - $12,000

= $378,000

We simply deduct the credit balance from the estimated balance so that the correct amount could arrive

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The graph shows the number of cubic feet of water used overtime at a waterpark that is open during the hours and the table. At t
iren2701 [21]

The graph is an illustration of a linear equation, where

  • <em>The cubic feet per minute is 31.25</em>
  • <em>The cubic feet per hour is 1875</em>
  • <em>15931.25 cubic feet of water will be used at the water park on Tuesday</em>

<em />

From the graph, we have:

(x_1,y_1) = (1,25)

(x_2,y_2) = (5,150)

The unit rate is calculated as follows:

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{150-25}{5-1}

m = \frac{125}{4}

<em />m = 31.25<em> cubic feet per minute</em>

The unit rate per hour is as follows

m = 31.25 \times 60

<em />m = 1875<em> cubic feet per hour</em>

The equation in hours is as follows:

y = m(x - x_1) + y_1

Where:

m = 1875

(x_1,y_1) = (1/60,25) ---- in hours

So, we have:

y = 1875(x - 1/60) + 25

y = 1875x - 31.25 + 25

y = 1875x -6.25

<u>The water park runs 8.5 hours on Tuesday (i.e. 11am to 7:30pm)</u>

So, we have:

y = 1875 \times 8.5 -6.25

y = 15931.25

Hence, 15931.25 cubic feet will be used at the water park on Tuesday

Read more about linear equations at:

brainly.com/question/11897796

6 0
3 years ago
Assumptions underlying the independent-measures ANOVA Which of the following are assumptions underlying independent-measures ana
Fofino [41]

Answer:

(b) The observations are independent of one another.

(d) Each of the populations of scores from which the samples are drawn has the same variance.

Step-by-step explanation:

Analysis of Variance(ANOVA) is used to compare the means of two or more samples using F-distribution.

The ANOVA has assumption based on dependent and independent variables. These are:

  1. The data should be distributed normally.
  2. The variance should be equal for population.
  3. The data should be independent from each other.
  4. Sample size should be greater than 20.

Thus, Option (b) and (d) are the only assumption here that follow the ANOVA.

7 0
3 years ago
I need y’all please help number 6
Anni [7]

Answer:

3rd option

Step-by-step explanation:

5x+500>1500

5 0
3 years ago
Helpp!!<br> Simplify : [( 4 1/6 + 2 1/3 ) ÷ 4 1/3 ] - 1 1/2
Nadusha1986 [10]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{0}}}}}

Step-by-step explanation:

\sf{ [ (4 \frac{1}{6}  + 2 \frac{1}{3} )  \div 4 \frac{1}{3}] -  1\frac{1}{2} }

Convert the mixed numbers into improper fraction

\longrightarrow{ \sf{ [ ( \frac{25}{6}  +  \frac{7}{3} ) \div  \frac{13}{3}] -  \frac{3}{2}}}

Add the fractions : 25 / 6 and 7 / 3

While performing addition or subtraction of unlike fractions, you have to express the given fractions into equivalent fractions of common denominator and add or subtract as we do with like fraction.

To do so, first take the L.C.M of 6 and 3 which results to 6

\longrightarrow\sf{ [( \frac{25 + 7 \times 2}{6} ) \div  \frac{13}{3} ] -  \frac{3}{2}}

\longrightarrow{ \sf{ [( \frac{25 + 14}{6} )  \div  \frac{13}{3}  ] -  \frac{3}{2} }}

\longrightarrow{ \sf{ [ \frac{39}{6}  \div  \frac{13}{3}] -  \frac{3}{2} }}

Multiply the dividend by the reciprocal of the divisor.

Reciprocal of any number or fraction can be obtained by interchanging the position of numerator and denominator

\longrightarrow{ \sf{ [  \frac{39}{6}  \times  \frac{3}{13} ] -  \frac{3}{2}}}

To multiply one fraction by another, multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term

\longrightarrow{ \sf{ [  \frac{39 \times 3}{6 \times 13} ] -  \frac{3}{2}}}

\longrightarrow{ \sf{ [  \frac{117}{78}  ] -  \frac{3}{2} }}

\longrightarrow{ \sf{ \frac{3}{2}  -  \frac{3}{2} }}

While performing the addition or subtraction of like fractions , you just have to add or subtract the numerator respectively in which the denominator is retained same

\longrightarrow{ \sf{ \frac{3 - 3}{2} }}

Subtract 3 from 3

\longrightarrow{ \sf{ \frac{0}{2}}}

Divide 0 by 2

\longrightarrow{ \sf{0}}

Hope I helped!

Best regards!

3 0
3 years ago
Determine the area and perimeter​
frosja888 [35]

Answer:

Area is the total surface covered by the shape and perimeter is the total length of the shape.

4 0
3 years ago
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