The domain of a function is the set of values of x for which a value of y exists. In this case, the only way that a value of y would not exist is for a denominator to equal to zero. If this function is f(x) = 1/(x+1) + 5, then we must find the values of x for which the denominator (x+1) = 0, which is at x = -1.
Therefore the domain is all real numbers except x = -1. In interval notation this can be written as (-infinity, -1), (-1, infinity).
Answer:
3/4, 6/8
Step-by-step explanation:
12/4 is 3. 16/4 is 4, repeat for the other one with the number 3
By synthetic division,
-5 | 1 -6 -42 79
. | -5 55 -65
- - - - - - - - - - - - - - - - -
. | 1 -11 13 14


When

, you're left with a remainder of 14.
Answer:

Step-by-step explanation:
Arithmetic sequence:

Here a is the first term and d is the common difference.
⇒
------------(I)
⇒ a + 19d = 100 ---------(II)
Subtract equation (I) from (II)
(I1) a + 19d = 100
(II) a + 13d = 46
<u>- - -</u>
6d = 54
d = 54 ÷ 6

Substitute d = 9 in equation(I) and find 'a',
a + 13*9= 46
a + 117 = 46
a = 46 - 117
a = -71

= -71 + 18
= -53

= -71 + 54
= -17

= -71 + 9*n - 1 *9
= -71 + 9n - 9
= -71 - 9 + 9n
= - 80 + 9n
Answer:
2/21
Step-by-step explanation:
2/21 is the answer...........that is the fraction......
x+1/3=3/7
x=3/7-1/3
LCM=21
x=9/21-7/21
x=2/21