On a piece of paper graph this system of equations y=x-8 y=x^2-2x-3
1 answer:
Answer:
The system of equations has no solution
The graph in the attached figure
Step-by-step explanation:
we have
-----> equation A
----> equation B
using a graphing tool
we know that
The solution of the system of equations is the intersection point both graphs
In this problem the graphics do not intersect
see the attached figure
therefore
The system of equations has no solution
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Answer:
The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
Step-by-step explanation:
A normal-distribution is an accurate symmetric-distribution of experimental data-values.
If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.
If X N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variates is known as the standard normal distribution.
Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
Answer:
a) P=0.535
b) P=0.204
c) P=0.286
Step-by-step explanation:
The exponential distribution is expressed as
In this example, λ=1/8=0.125 min⁻¹.
a) The probability of having to wait more than 5 minutes
b) The probability of having to wait between 10 and 20 minutes
c) The exponential distribution is memory-less, so it is independent of past events.
If you have waited 5 minutes, the probability of waiting more than 15 minutes in total is the same as the probability of waiting 15-5=10 minutes.