Finding the Area of a Triangle
1 answer:
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Answer:
A trapezoid ABCD is show below,
AB || CD
AC and BD are diagonals intersecting at P.
(a)
In Δ ABC and ABD,
Area of triangle ABC = Area of triangle ABD
Because,
Area of triangle ABC = 1/2 × Base × Height
Base = AB
Height = h, which is same for both the triangle that's why,
Area of triangle ABC = Area of triangle ABD
(b)
As we know that,
Area of triangle ABC = Area of triangle ABD
On subtracting the area of triangle ABP from both the triangles, we get
Area of triangle ABC - area of triangle ABP = Area of triangle ABD - area of triangle ABP
⇒ area of triangle BCP = area of triangle DAP
Hence, triangles BCP and DAP have the same area.
(c)
In triangle ABP and CDP,
∠ABP = ∠CDP (opposite interior angles are equal between two parallel lines)
∠APB = ∠CPD (opposite angles are equal)
∠BAP = ∠DCP (opposite interior angles are equal between two parallel lines)
Therefore,
By AAA similarity
Triangles ABP and CDP are similar.
(d)
In triangle BCP and DAP,
Only ∠BCP = ∠APD (opposite angles are equal).
Therefore,
Triangles BCP and DAP need not be similar.
Given Information:
Mean = μ = $282.45
Standard deviation = σ = $64.50
Sample size = n = 100
Confidence level = 95%
Required Information:
95% Confidence interval = ?
Answer:
95% Confidence interval = ($269.81, $295.09)
Step-by-step explanation:
We are given a Normal Distribution, which is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.
What is Confidence Interval?
The confidence interval represents an interval that we can guarantee that the target variable will be within this interval for a given confidence level.
The confidence interval is given by
Where is the mean and MoE is the margin of error given by
Where σ is the standard deviation, n is the sample size and is the z-score corresponding to 95% confidence level.
Finally, the confidence interval is
Therefore, we are 95% sure that the true population mean amount spent per day by a family of four visiting Niagara Falls is within the interval of ($269.81, $295.09)