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vova2212 [387]
3 years ago
7

Mable has 185 dollars worth of apples. Each apple is worth more then 3 dollars but less then 10 dollars. The number has four let

ters and in an odd number. The number is a prime number. How much is each apple worth? (REMEMBER THE NUMBER HAS TO GO INTO 185 EQUALLY)
Mathematics
1 answer:
velikii [3]3 years ago
6 0

Answer:

The worth of each of Mable's apples is $5

Step-by-step explanation:

 Extracting the key information from the question:

***Mable has apples that are worth a combined 185 dollars.

*** One apple from Mable's apples worth more than three ($3) dollars but less than ten ($10) dollars.

***The cost of one apple is a number that has four letters.

*** That number (the cost) of one apple is also a prime number.

*** We are required to find or determine the worth of one of Mable's apples.

   Now, one of the clues given to us which we may use to figure out the cost or worth of one apple is that the apple is worth more than three dollars ($3) but worth less than ten dollars ($10). This means that each Mable's apple may worth $4 or $5 or $6 or $7 or $8 or $9. That is one of Mable's apples worth from $4 to $9

   Another clue to solving this puzzle is that the worth of one apple in dollars is a prime number. This implies that one of Mable's apples may worth either five dollars ($5) or seven dollars ($7).

   

  The next clue for unravelling this mystery is that all Mable's apples are worth a combined $185. This then means that the worth of each apple (the number) must be able to divide 185.

   Since $7 and $5 are the only two figures left standing, we will then try and see which one of them will be able to do divide the number "185".

 185/7  = 26 remainder 3

 185/5  = 37 remainder 0

 The final clue in the question is that the worth of each of Mable's apples is a figure/number that has only letters:

$7 SEVEN has = 5 letters

$5 FIVE has = 4 letters

 This now brings us to the conclusion that the worth of each of Mable's apples is five dollars ($5)  since it meets all the requirements and clues in the question.

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The prices of all college textbooks follow a bell-shaped distribution with a mean of $113 and a standard deviation of $12. Using
Soloha48 [4]

Step-by-step explanation:

In statistics, the empirical rule states that for a normally distributed random variable,

  • 68.27% of the data lies within one standard deviation of the mean.

  • 95.45% of the data lies within two standard deviations of the mean.

  • 99.73% of the data lies within three standard deviations of the mean.

In mathematical notation, as shown in the figure below (for a standard normal distribution), the empirical rule is described as

                             \Phi(\mu \ - \ \sigma \ \leq X \ \leq \mu \ + \ \sigma) \ = \ 0.6827 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi(\mu \ - \ 2\sigma \ \leq X \ \leq \mu \ + \ 2\sigma) \ = \ 0.9545 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi}(\mu \ - \ 3\sigma \ \leq X \ \leq \mu \ + \ 3\sigma) \ = \ 0.9973 \qquad (4 \ \text{s.f.})

where the symbol \Phi (the uppercase greek alphabet phi) is the cumulative density function of the normal distribution, \mu is the mean and \sigma is the standard deviation of the normal distribution defined as N(\mu, \ \sigma).

According to the empirical rule stated above, the interval that contains the prices of 99.7% of college textbooks for a normal distribution N(113, \ 12),

                \Phi(113 \ - \ 3 \ \times \ 12 \ \leq \ X \ \leq \ 113 \ + \ 3 \ \times \ 12) \ = \ 0.9973 \\ \\ \\ \-\hspace{1.75cm} \Phi(113 \ - \ 36 \ \leq \ X \ \leq \ 113 \ + \ 36) \ = \ 0.9973 \\ \\ \\ \-\hspace{3.95cm} \Phi(77 \ \leq \ X \ \leq \ 149) \ = \ 0.9973

Therefore, the price of 99.7% of college textbooks falls inclusively between $77 and $149.

5 0
2 years ago
Prove or disprove that the point (√5, 12) is on the circle centered at the origin and containing the point (-13, 0). Show your w
pav-90 [236]

Using the equation of the circle, it is found that since it reaches an identity, the point (√5, 12) is on the circle.

<h3>What is the equation of a circle?</h3>

The equation of a circle of center (x_0, y_0) and radius r is given by:

(x - x_0)^2 + (y - y_0)^2 = r^2

In this problem, the circle is centered at the origin, hence (x_0, y_0) = (0,0).

The circle contains the point (-13,0), hence the radius is found as follows:

x^2 + y^2 = r^2

(-13)^2 + 0^2 = t^2

r^2 = 169

Hence the equation is:

x^2 + y^2 = 169

Then, we test if point (√5, 12) is on the circle:

x^2 + y^2 = 169

(\sqrt{5})^2 + 12^2 = 169

25 + 144 = 169

Which is an identity, hence point (√5, 12) is on the circle.

More can be learned about the equation of a circle at brainly.com/question/24307696

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6 0
3 years ago
Translate the graph according to the rule (x, y) → (x , y – 2).
Rudik [331]
The fourth one, because when changing the y, the y coordinate changes
4 0
4 years ago
Verify that y1(t) = 1 and y2(t) = t ^1/2 are solutions of the differential equation:
Papessa [141]

Answer: it is verified that:

* y1 and y2 are solutions to the differential equation,

* c1 + c2t^(1/2) is not a solution.

Step-by-step explanation:

Given the differential equation

yy'' + (y')² = 0

To verify that y1 solutions to the DE, differentiate y1 twice and substitute the values of y1'' for y'', y1' for y', and y1 for y into the DE. If it is equal to 0, then it is a solution. Do this for y2 as well.

Now,

y1 = 1

y1' = 0

y'' = 0

So,

y1y1'' + (y1')² = (1)(0) + (0)² = 0

Hence, y1 is a solution.

y2 = t^(1/2)

y2' = (1/2)t^(-1/2)

y2'' = (-1/4)t^(-3/2)

So,

y2y2'' + (y2')² = t^(1/2)×(-1/4)t^(-3/2) + [(1/2)t^(-1/2)]² = (-1/4)t^(-1) + (1/4)t^(-1) = 0

Hence, y2 is a solution.

Now, for some nonzero constants, c1 and c2, suppose c1 + c2t^(1/2) is a solution, then y = c1 + c2t^(1/2) satisfies the differential equation.

Let us differentiate this twice, and verify if it satisfies the differential equation.

y = c1 + c2t^(1/2)

y' = (1/2)c2t^(-1/2)

y'' = (-1/4)c2t(-3/2)

yy'' + (y')² = [c1 + c2t^(1/2)][(-1/4)c2t(-3/2)] + [(1/2)c2t^(-1/2)]²

= (-1/4)c1c2t(-3/2) + (-1/4)(c2)²t(-3/2) + (1/4)(c2)²t^(-1)

= (-1/4)c1c2t(-3/2)

≠ 0

This clearly doesn't satisfy the differential equation, hence, it is not a solution.

6 0
3 years ago
What would the markup be???
Alja [10]
Hello!

To find the markup you have to subtract the selling price from the store price so

91 - 65 = 26

So there is a $26 markup

Hope this helps!
5 0
3 years ago
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