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storchak [24]
3 years ago
11

36= 2² x 3² how do i get the number to my prime factor

Mathematics
2 answers:
mojhsa [17]3 years ago
5 0

Answer:

add up the exponents on each prime number

Step-by-step explanation:

2^2= 2x2

3^2=3x3

so 36=2^2x3^2=2x2x3x3

Anni [7]3 years ago
4 0

Answer:

3

Step-by-step explanation:

36

| \  

18   2

| \  

9   2

| \  

3   3

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Each student will receiver $16.25
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Maria is comparing the prices of two window cleaning companies. Company A charges $6 per window and an additional $12 as service
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8 0
3 years ago
The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.
andrezito [222]

Answer:

Given the equation: 3x^2+10x+c =0

A quadratic equation is in the form: ax^2+bx+c = 0 where a, b ,c are the coefficient and a≠0 then the solution is given by :

x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a} ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}

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x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}

Also, it is given that the difference of two roots of the given equation is 4\frac{2}{3} = \frac{14}{3}

i.e,

x_1 -x_2 = \frac{14}{3}

Here,

x_1 = \frac{-10 + \sqrt{100- 12c}}{6} ,     ......[2]

x_2= \frac{-10 - \sqrt{100- 12c}}{6}       .....[3]

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\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}

simplify:

\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}

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\sqrt{100- 12c} = 14

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100-12c -100= 196-100

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c = 8

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x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}

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