What are your thoughts on the loss of trees? Explain. (At least 4 sentences long).

1 answer:

6 0

Answer: My thoughts on the loss of trees is quite disappointing due to the fact that we need them to survive. The loss of trees is not something good for the environment because many animals need it for shelters. It could cause animals to be endangered because they can’t hide from predators or hunters. Hopefully the trees will start increasing in 2020.

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The weight of baby elephants is believed to be Normally distributed, with a mean of 123.5 pounds. The average weight of a random

alexgriva [62]

Answer:

The standard error of the mean is 1.91 pounds

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation, which is also called standard error of the mean, is $s = \frac{\sigma}{\sqrt{n}}$

In this problem we have that:

$\sigma = 11.3, n = 35$

$s = \frac{11.3}{\sqrt{35}} = 1.91$

The standard error of the mean is 1.91 pounds

3 0

3 years ago

Read 2 more answers

Explain how to easily decide whether x - 6 is a factor of the polynomial P(x) = x ^ 7 - 5x ^ 5 + 2x ^ 4 - x ^ 2 + 9 without perf

madreJ [45]

$\text{According to the factor theorem,}\\\\x-a~ \text{is a factor of}~ f(x)~ \text{if}~ f(a) = 0, ~ \text{where}~ a \in\mathbb{R}\\\\\text{Given that,}\\ \\P(x) = x^7 -5x^5 +2x^4 -x^2 +9\\\\P(6) = 6^7 -5\cdot 6^7 +2 \cdot 6^4 -6^2 +9 = 243621 \neq 0\\\\\text{Since} ~ P(6)\neq 0~, ~ x -6 ~ \text{is not a factor of P(x).}$